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1 year ago

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On the drawing for a house plan, the master bedroom is rectangular and has dimensions of 2.25 inches by 2.5 inches. If the scale

of the drawing is 1/8 inch =1 foot, What is the actual area of the master bedroom?

1 answer:

satela [25.4K]1 year ago

8 0

The answer is 16 metric units by the quarter mile

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Fifty specimens of a new computer chip were tested for speed in a certain application, along with 50 specimens of chips with the

Murljashka [212]

Answer:

Under 99% confidence level we can say that mean speed of the new chips is greater than that of the old chips

Step-by-step explanation:

$H_{0}$ : Mean speed of the new chip is the same as the old chip

$H_{a}$ : Mean speed of the new chip is greater than the old chip

to calculate the z-statistic we can use the formula:

z= $\frac{M_{n}-M_{o}}{\sqrt{\frac{s_{n}^2}{N_{n}} +\frac{s_{o}^2}{N_{o}} } }$

if we put the numbers then

z= $\frac{495.6-481.2}{\sqrt{\frac{19.4^2}{65}} +\frac{14.3^2}{65} } }$ =4.8171

The probability of this z-statistic is < 0.001 Therefore Under 99% confidence level we can say that mean speed of the new chips is greater than that of the old chips

4 0

2 years ago

Mai bought eleven 12-ounce bags of

ella [17]

Answer:

8.25 pounds

Step-by-step explanation:

When you multiply 12 and 11 you get 132. So then you would have to divided the total amount of ounces by 16 to get the amount of pounds

5 0

2 years ago

An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by

GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis $H_0 : \mu_1 - \mu_2 >2$ ,

and the alternative hypothesis $H_1: \mu_1 - \mu_2 \leq 2$ .

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

$s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05$ ,

where $n_1 = 12, n_2 =10, s_1 =4, s_2 = 5$ .

The mean of material 1 and material 2 are $\mu_1 =85, \mu_2=81$ respectively and mean difference $d$ is equal to 4. The hypothesize difference $d_0$ is equal to 2.

To find the T-score, we use the following formula

$T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}$

Substituting all the values into the T-score formula gives us $T = 1.04$ , and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

6 0

1 year ago

Seth is trying to find the unit price for a package of blank compact discs on sale at 10 for $5.49. Find his mistake and correct

uysha [10]

If you do not mind me asking, what did Seth write? Us helpers cannot answer it if we do not have the full question. I apologize if this seems rude.

6 0

2 years ago

Read 2 more answers

A movie theater sells popcorn in bags of different sizes. The table shows the volume of popcorn and the price of the bag.

scoundrel [369]

Answer:

<em>The price for a 60-ounce bag of popcorn would be $16</em>

Step-by-step explanation:

<u>Function Modeling</u>

The behavior of some parameters that depend on a set of variables can be modeled in several ways, like linear, quadratic, exponential, logarithmic, among many others.

The selection of the model is often a complex decision that involves statistics and data analysis.

The question provides us with four points where the volume of popcorn bags and the price in dollars. The easiest function that can be used is the line.

The equation of a line of the volume V and the price p can be found with the expression

$\displaystyle p-p_1=\frac{p_2-p_1}{V_2-V_1}(V-V_1)$

We'll use the first two values (6,10) (8,20)

$\displaystyle p-6=\frac{8-6}{20-10}(V-10)$

Simplifying and rearranging, we get the model

$\displaystyle p(V)=\frac{1}{5}V+4$

To test the accuracy of the model, we compute the values of p for V=35 and for V=48

$\displaystyle p(35)=\frac{1}{5}(35)+4=11$

$\displaystyle p(48)=\frac{1}{5}(48)+4=13.6$

Since the computed values are equal to those of the table, the model is accurate. We can now predict the price for V=60

$\displaystyle p(60)=\frac{1}{5}(60)+4=16$

The price for a 60-ounce bag of popcorn would be $16

6 0

2 years ago