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Sidana [21]
2 years ago
15

30 POINTS!! Which construction correctly shows how to bisect ∠X?

Mathematics
2 answers:
Colt1911 [192]2 years ago
7 0
It would be a) j and l.
agasfer [191]2 years ago
6 0
The correct answer is B) J and m
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Ryan’s mom randomly chooses two days each week for Ryan to do his chores. What is the probability that she picks Saturday and Su
torisob [31]
There are a total of 7C2 of options for Ryan's mom to choose.

If Ryan's mom picks Saturday and Sunday, this is the only 1 option in those 7C2 of options. Thus, the propability is (1 / 7C2) × 100% = 4.762%.
4 0
2 years ago
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Noelle stands at the edge of a cliff and drops a rock. The height of the rock is given by the function f(x)-4.9x2 + 15, where c
Oxana [17]
A graphing calculator shows the rocks are at the same height 1.5 seconds after they are released.

That height is 3.975 meters.

_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975

3 0
2 years ago
The letters of the word mississippi are placed in a hat. what is the probability that the first two letters drawn are both i if
allochka39001 [22]
For the first letter drawn, there are no conditions/restrictions we need to consider. So, the number of ways to draw an i is:
\text{Draw(i): } \frac{4}{11}

For the second draw, the i is not replaced. That means, we've shrunk the sample space because we're dealing with less elements for the second draw. Firstly, one i disappears since we picked an "i" and there are 10 elements left, not 11.

Thus, to draw the second i, we have:
\text{Draw(ii): } \frac{3}{10}

\text{P(drawing 2 i's): } \frac{4}{11} \cdot \frac{3}{10} = \frac{12}{110} = \frac{6}{55}
3 0
2 years ago
Alice wants to estimate the percentage of people who plan on voting yes for the upcoming school levy. She surveys 380 individual
goblinko [34]

Answer: (0.641, 0.719)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Given : Level of significance : 1-\alpha:0.90

Then , significance level : \alpha: 1-0.90=0.10

Since , sample size : n=380 , i.e. a large sample.

Critical value : z_{\alpha/2}=1.645

Also, the proportion of individuals plan on voting yes :-

\hat{p}=\dfrac{260}{380}\approx0.68

Then , the confidence interval at the 90% confidence level will be :-

0.68\pm(1.645)\sqrt{\dfrac{0.68(1-0.68)}{380}}\\\\\approx0.68\pm0.039\\\\=(0.68-0.039, 0.68+0.039=(0.641,\ 0.719)

Hence, the confidence interval at the 90% confidence level= (0.641, 0.719)

3 0
2 years ago
A wire 31 cm long is cut into two pieces. the longer piece is 5 cm longer than the shorter piece. find the length of the shorter
oksian1 [2.3K]
Let the longer piece be x+5
Let the shorter piece by x

Both the wires together make 31cm so

x + x + 5 = 31
2x + 5 = 31
2x = 26
x=13

The shorter piece of the wire is 13cm.
8 0
2 years ago
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