Remember that an extraneous solution of an equation is a solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation.
First, we are going to solve our equation algebraically:
Step 1 simplify the equation:


Step 2 subtract 5 from both sides of the equation:


Step 3 square both sides of the equation:


Next, we are going to replace our solution in our original equation and check if it is a valid solution:




Since 9 is not equal to 1,
is not valid solution of the equation; therefor it is an extraneous solution.
We can conclude that the correct answer is: x = 16, solution is extraneous
Answer:
The value of the 3 is 30,000,000.
Step-by-step explanation:
From the digit at the right, you go multiplying each element by 10 powered to a counter that starts at zero and increases at every digit. So:
Our counter is i
i = 0;
v(7) is the value of the 7

i = 1;
v(5) is the value of the 5

i = 2;
v(1) is the value of the 1

i = 3;
v(5) is the value of the 5

i = 4;
v(9) is the value of the 9

i = 5;
v(6) is the value of the 6

i = 6;
v(8) is the value of the 8

i = 7;
v(3) is the value of the 3

The value of the 3 is 30,000,000.
Answer:
a
Step-by-step explanation: