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Aleks04 [339]
1 year ago
11

(25 points, please help! Brainliest!) Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home.

She has made the following scale drawing as her model. The scale used on the drawing is 1:6.
As you can see, the "H" is going to be painted brick red in the center of a rectangular beige background. This means the distance from the "H" to the top of the picture will be the same as the distance from the "H" to the bottom of the picture. Similarly, the distance from the "H" to the left side of the picture will be the same as the distance from the "H" to the right side of the picture. Finally, each segment of the "H" will have the same width.


Mrs. Hanger decides to change the scale of her drawing from 1:6 to 1:4.


1. Is the new scale drawing larger or smaller than the original scale drawing? Use complete sentences to explain your reasoning.

2. What are the dimensions of the painting on the new scale drawing?

Mathematics
1 answer:
disa [49]1 year ago
7 0

Answer:

the new scale is the same length as the original scale

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Kari bought 3 boxes of cookies to share with a book club. Each box contains 12 cookies. The expression represents the number of
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<u>ANSWER:</u>

Kari bought 3 boxes of cookies to share. The algebraic expression is \frac{36}{x}

<u>Solution:</u>

Given, Kari bought 3 boxes of cookies to share with a book club.  

Each box contains 12 cookies.  

So, in total we have 3 x 12 cookies = 36 cookies.

Now, we have to find how many cookies can each person p will get.

Let, the total number of persons be x.

Then, after equally sharing the cookies,

\text { Number of cookies with each person }=\frac{\text {number } of \text { cookies available.}}{\text {total number of persons}}

=\frac{36}{x} \text { cookies. }

Hence, the algebraic expression is \frac{36}{x}

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Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
GuDViN [60]

Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Consider the given matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B is

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is given that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

On comparing corresponding elements of both matrices, we get

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Therefore, the required values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

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Answer:

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Step-by-step explanation:

Let the three consecutive even integers representing the sides of the triangle PQR be x, (x +2) and (x + 4).

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