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2 years ago

For what natural values of n is the difference (2−2n)−(5n−27) positive?

Mathematics

2 answers:

pashok25 [27]2 years ago

4 0

(2−2n)−(5n−27) >0

distribute

2-2n -5n +27 >0

combine like terms

-7n +29 >0

subtract 29 from each side

-7n> -29

divide by -7 (flips the inequality)

n < -29/-7

n <4.14

natural numbers are 1,2,3,4......

n must be 1,2,3,4

Answer: 1,2,3,4

valkas [14]2 years ago

3 0

(2 - 2n) - (5n -27) > 0

-7n +27 + 2 > 0

-7n > -29

n < 29/7 < 4.143

So the natural values of n to make the expression positive are

1, 2, 3 and 4 (answer)

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Answer:

$h=588$

Step-by-step explanation:

Given the fraction $\dfrac{4,704}{h}$

Consider its numerator and factor it:

$4,704=2^5\cdot 3\cdot 7^2$

You cann not take the cube root from $3, 7^2, 2^5,$ you can only take the cube root from $2^3$ , then the smallest whole number $h$ such that $\dfrac{4,704}{h}$ is a cube number is

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When $h=588,$

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Answer:

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Step-by-step explanation:

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let Leo's speed = x mile/hr

so Ethan speed = (x + 6) miles per hour

Distance = Speed × Time

so distance traveled by Leo in 2 hours = x × 2 = 2x

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over the course of numbering every page in a book, a mechanical stamp printed 2929 individual digits. How many pages does the bo

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1. Page 1-9 (1digit/page x 9page) = 9 digits = 9 page

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Hope this answer will be a good help for you.

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