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boyakko [2]
1 year ago
8

A car manufacturer advertises that its new sports car has a turning radius of only 16 feet. The front tires are 4.5 feet apart.

The path of the inside and outside tires is shown in the diagram. Compare the distance that the outside tires must travel to the distance the inside tires must travel in order to make a complete circle.

Mathematics
2 answers:
Simora [160]1 year ago
3 0

Answer:

12.5..............................

Sergeu [11.5K]1 year ago
3 0

Answer:

Solution given:

radius of small circle[r]=16-4.5ft=11.5ft

radius of large circle[R]=16ft

nowcircumference of small circle=2πr=2*3.14*11.5=72.22ft

circumference of large circle=2πR=2*3.14*16=100.48ft

distance that the outside tires must travel to the distance the inside tires must travel in order to make a complete circle

=\frac{100.48}{72.22}=\frac{32}{23}

ratio is <u>32:23.</u>

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Answer: y = -9

Step-by-step explanation:

(-2y) + y - 3 = 6

(-y) - 3 = 6

-y = 9

y = -9

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2 years ago
Nikki drew a rectangle with a perimeter of 18 units on a coordinate grid. Two of the vertices were (4, –3) and (–1, –3). What co
Talja [164]

Answer:

There are two possible solutions for the other two vertices of the rectangle:

(i) (4, 1), (-1, 1), (ii) (4, -7), (-1, -7)

Step-by-step explanation:

Geometrically speaking, the perimeter of a rectangle (p) is:

p = 2\cdot b + 2\cdot h (1)

Where:

b - Base of the rectangle.

h - Height of the rectangle.

Let suppose that the base of the rectangle is the line segment between (4, -3) and (-1, -3). The length of the base is calculated by Pythagorean Theorem:

b = \sqrt{[(-1)-4]^{2}+[(-3)-(-3)]^{2}}

b = 5

If we know that p = 18 and b = 5, then the height of the rectangle is:

2\cdot h = p-2\cdot b

h = \frac{p-2\cdot b}{2}

h = \frac{p}{2}-b

h = 4

There are two possible solutions for the other two vertices of the rectangle:

(i) (4, 1), (-1, 1), (ii) (4, -7), (-1, -7)

8 0
1 year ago
If LN=54 and LM=31, find MN
kirza4 [7]
In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN. 

The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
             LN + LM = MN

We are given with the lengths of the smalller segments and substituting the known values,
             MN = 54 + 31
            MN = 85

<em>ANSWER: MN = 85</em>
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The coordinates of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) . Which statement correc
Pavlova-9 [17]

Answer:

C.Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

Complete question:

A. Quadrilateral ABCD is not a rhombus because opposite sides are parallel but the four sides do not all have the same length.

B. Quadrilateral ABCD is a rhombus because opposite sides are parallel and all four sides have the same length.

C. Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

D. Quadrilateral ABCD is not a rhombus because there is only one pair of opposite sides that are parallel.

Step-by-step explanation:

Rhombus states that a parallelogram with four equal sides and sometimes one with no right angle.

Given: The coordinate of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) .

The condition for the segment (x_{1},y_{1}), (x_{2},y_{2})  to be parallel to (x_{3},y_{3}),  (x_{4},y_{4}) is matching slopes;

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}= \frac{y_{4}-y_{3}}{x_{4}-x_{3}} \\(y_{2}-y_{1}) \cdot (x_{4}-x_{3}) =(y_{4}-y_{3}) \cdot (x_{2}-x_{1})---->1

So, we have to check that AB || CD and AD || BC

First check AB || CD

A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2)

substitute in [1],

(5-3) \cdot (-2-3) = (-2-1) \cdot (-1-(-6))2 \cdot -5 = -3 \cdot 5

-10 ≠ -15

Similarly,

check AD || BC

A(−6, 3) , D(−2, −2) , B(−1, 5) and C(3, 1)

Substitute in [1], we have

(-2-3) \cdot (3-(-1)) = (1-5) \cdot (-2-(-6))-5 \cdot 4 = -4 \cdot 4

-20 ≠ -16.

Both pairs of sides are not parallel,

therefore, Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

8 0
1 year ago
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