find the slope of the line on the graph write your answer as a fraction or a whole number not a mixed number or decimal

A catering company prepared and served 300 meals at an anniversary celebration last week using eight workers. The week before, s

swat32

Answer:

II case.

Step-by-step explanation:

Given that a catering company prepared and served 300 meals at an anniversary celebration last week using eight workers.

The week before, six workers prepared and served 240 meals at a wedding reception.

Productivity is normally measured by number of outputs/number of inputs

Here we can measure productivity as

no of meals served/no of workers

In the I case productivity = $\frac{300}{8} \\=37.5$

In the II case productivity = $\frac{240}{6} \\=40$

Obviously II case productivity is more as per worker 40 meals were served which is more than 37.5 meals per worker in the I case.

3 0

2 years ago

Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L 18, start fraction, start text, L, end text, divided

Fiesta28 [93]

Answer:

Uche's pumping rate is <u>300 mL/s</u>.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

18 L/min = 16.6667 × 18 mL/s.

18L/min = 300 mL/s.

Therefore, Uche's pumping rate is 300 mL/s.

8 0

1 year ago

(1 point) Let P(t) be the performance level of someone learning a skill as a function of the training time t. The derivative dPd

monitta

Answer:

$P(t)=M+Ce^{-kt}$

Step-by-step explanation:

Given the differential model

$\dfrac{dP}{dt}=k[M-P(t)]$

We are required to solve the equation for P(t).

$\dfrac{dP}{dt}=kM-kP(t)\\$Add kP(t) to both sides\\\dfrac{dP}{dt}+kP(t)=kM\\$Taking the integrating factor\\e^{\int k dt} =e^{kt}\\$Multiply all through by the integrating factor\\\dfrac{dP}{dt}e^{kt}+kP(t)e^{kt}=kMe^{kt}\\\dfrac{dP}{dt}e^{kt}=kMe^{kt}\\(Pe^{kt})'=kMe^{kt} dt\\$Take the integral of both sides with respect to t\\\int (Pe^{kt})'=\int kMe^{kt} dt\\Pe^{kt}=kM \int e^{kt} dt\\Pe^{kt}=\dfrac{kM}{k} e^{kt} + C_0, C_0$ a constant of integration$

$Pe^{kt}=Me^{kt} + C\\$Divide both side by e^{kt}\\P(t)=M+Ce^{-kt}\\P(t)=M+Ce^{-kt}\\$Therefore:\\P(t)=M+Ce^{-kt}$

4 0

2 years ago

A bamboo shoot is 20 inches tall at the zero and gross 24 inches each day which functions show below can be used to determine he

ale4655 [162]

It is definitely D because on part 1 n=24n+20 and if n equals 0 than 24 (0) +20= 20 and that is true. on part 2 if n =0 than 24 (0)+ 20 (0-1)=20 than 20 (-1)=20 -20= 20. that statement is false because-20 does not equal 20. AND for part 3 n=1 and f (1-1) + 24= 44 so f (0) + 24 =44 and keep in mind f (0) equals 20 so 44=44 because 24+20 is 44. so that is a true statement too

8 0

2 years ago

Read 2 more answers

PLEASE HELP I NEED THIS!!

Alja [10]

Answer:

the first one

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers