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1 year ago

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Four points are labeled on the number line. P. Q. R. S. Which point represents the value of the absolute value of negative 1 ove

r 2?

1 answer:

Lostsunrise [7]1 year ago

5 0

Answer:

See Explanation

Step-by-step explanation:

Incomplete question, as the number line is not attached. However, the solution is as follows:

Let y be the absolute value of -1/2 So:

$y = |-\frac{1}{2}|$

The absolute sign removes all negation. So:

$y = \frac{1}{2}$

This means that the point at the label $\frac{1}{2}$ or $0.5$ is the solution to the question.

<em>Take for instance, the attached image has point Q at </em> $\frac{1}{2}$ <em>.</em>

<em>Hence, Q is the absolute value of -1/2</em>

<em />

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We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

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When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

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Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

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