Ask question

Ask question

All categories

1 year ago

10

Four points are labeled on the number line. P. Q. R. S. Which point represents the value of the absolute value of negative 1 ove

r 2?

1 answer:

Lostsunrise [7]1 year ago

5 0

Answer:

See Explanation

Step-by-step explanation:

Incomplete question, as the number line is not attached. However, the solution is as follows:

Let y be the absolute value of -1/2 So:

$y = |-\frac{1}{2}|$

The absolute sign removes all negation. So:

$y = \frac{1}{2}$

This means that the point at the label $\frac{1}{2}$ or $0.5$ is the solution to the question.

<em>Take for instance, the attached image has point Q at </em> $\frac{1}{2}$ <em>.</em>

<em>Hence, Q is the absolute value of -1/2</em>

<em />

You might be interested in

The graph of f(x) = |x| is transformed to g(x) = [X + 11-7. On which interval is the function decreasing?

puteri [66]

Answer:

The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

Step-by-step explanation:

* Lets explain how to solve it

- Decreasing function means a function with a graph that moves

downward as it is followed from left to right.

- For example, any line with a negative slope is decreasing function

- Lets look to the attached graph to understand the meaning of the

decreasing function

∵ f(x) = IxI ⇒ green graph

∵ g(x) = Ix + 1I - 7 ⇒ purple graph

- From the graph f(x) translated 1 unit to the left and 7 units down to

form g(x)

- The domains of f(x) and g(x) are all real numbers {x : x ∈ R}

- The range of f(x) is {y : y ≥ 0}

- The range of g(x) is {y : y ≥ -7}

# For f(x)

- The slope of the green line from (-∞ , 0) is negative

- The slope of the green line from (0 , ∞) is positive

# For g(x)

- The slope of the purple line from (-∞ , -1) is negative

- The slope of the purple line from (-1 , ∞) is positive

∵ The line with negative slope represent decreasing function

∴ The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

∴ The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

7 0

1 year ago

Kathy has $50,000 to invest today and would like to determine whether it is realistic for her to achieve her goal of buying a ho

olga_2 [115]

Answer:

a) About 12%

Step-by-step explanation:

We need to find the interest rate required to achieve her goal, so we will need to use the interest-compound formula:

$FV=PV(1+i)^{n}$

Where:

PV= Present Value

i= interest rate

FV= Future Value

n= number of periods

replacing the data provided:

$150.000=50.000(1+i)^{10}$

solving for i:

first, divide both sides by 50.000 to simplify the equation:

$3=(1+i)^{10}$

Take $10^{th}$ roots of both sides:

$1+i=$ ± $\sqrt[10]{3}$

solve for i:

$i=$ ± $\sqrt[10]{3} -1$

We get two answers, but we look for a coherent value. So we take the positive one:

$i=11.6123174$ ≈12

6 0

1 year ago

If 10a+10b=35, what is the average (arithmetic mean) of a and b?

worty [1.4K]

Answer:

1.75

Step-by-step explanation:

If a and b are two numbers, then their arithmetic mean is

$\dfrac{a+b}{2}$

Given:

$10a+10b=35$

Divide this equation by 10:

$a+b=3.5$

Now, divide it by 2:

$\dfrac{a+b}{2}=\dfrac{3.5}{2}\\ \\\dfrac{a+b}{2}=1.75$

6 0

2 years ago

What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1

marta [7]

First, we need to solve the differential equation.
$\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)$
This a separable ODE. We can rewrite it like this:
$-\frac{4}{y^2-8y}{dy}=dt$
Now we integrate both sides.
$\int \:-\frac{4}{y^2-8y}dy=\int \:dt$
We get:
$\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1$
When we solve for y we get our solution:
$y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}$
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8$
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.

3 0

1 year ago

melamori03 [73]

Answer:

The answer is C.

Step-by-step explanation:

The $13 he started off with is the y-intercept or the initial value, which is the point where x=0.

The x-intercept, or rate of change, is $8.50.

The slope intercept formula is y=mx+b, where m=8.5 and b=13.

The equation for this problem is y=8.5x+13.

So the answer is C

4 0

1 year ago