Misty Duncan had $73.90 in cash receipt last month. Her cash receipt

A white-tailed deer can sprint at speeds up to 30 miles per hour. American bison can run at speeds up to 3,520 feet per minute.

Paul [167]

3520/5280 = 2/3 of a mile per minute.

2/3 x 60 minutes per hour = 40 miles per hour.

40-30 = 10

Bison runs 40 miles per hour

The bison runs 10 miles an hour faster than the deer

8 0

1 year ago

Read 2 more answers

Find the absolute value of 3.1+(-6.3)

Sliva [168]

Answer:

3.2

Step-by-step explanation:

First, evalue what's inside of the absolute value:

3.1 + (-6.3) = -3.2

Now, since absolute value means the distance from the number to 0, the absolute value of -3.2 is the negation of -3.2:

|-3.2| = 3.2

7 0

1 year ago

On sunday 1/16 people who visit were senior citizens, 3/16 were infants, 3/8 were children and 3/8 were adults, how many of each

mamaluj [8]

Answer:

Out of total people visited the zoo on Sunday , 6.25% was senior citizen , 18.75% were infants , 35% were children and 35% were adult.

Step-by-step explanation:

let total number of people visited the group = x

so number of senior citizens = x × 1/16 = x/16

Percentage of senior citizens = (number of senior citizens ÷ total number of people visited the group) × 100

= (x/16 ÷ x) × 100 = 100/16 = 6.25%

number of infants = 3/16 × x = 3x/16

Percentage of infants =(number of infants ÷ total number of people visited the group) × 100 = (3x/16 ÷ x) × 100 = 300/16 = 18.75%

number of children = 3/8 × x = 3x/8

Percentage of children =(number of children ÷ total number of people visited the group) × 100 = (3x/8 ÷ x) × 100 = 300/8 = 37.5%

number of adults = 3/8 × x = 3x/8

Percentage of adults =(number of adults ÷ total number of people visited the group) × 100 = (3x/8 ÷ x) × 100 = 300/8 = 37.5%.

Hence we can conclude that Out of total people visited the zoo on Sunday , 6.25% was senior citizen , 18.75% were infants , 35% were children and 35% were adult.

4 0

2 years ago

Lavania is studying the growth of a population of fruit flies in her laboratory. After 6 days she had nine more than five times

MatroZZZ [7]

Answer:

Lavania observed 39 fruit flies after 6 days of observation

Step-by-step explanation:

Let x be the number of fruit flies on the first day of Lavania's study.

After 6 days she had nine more than five times as many fruit flies as when she began the study.

Five times as many fruit flies as when she began the study = 5x

Nine more than five times as many fruit flies as when she began the study=5x+9

The expression to find the population of fruit flies Lavania observed after 6 days is 5x+9

If she observes 20 fruit flies on the first day of the study, then x=6, then

$5x+9=5\cdot 6+9=30+9=39$

5 0

1 year ago

Find the distance from (4, −7, 6) to each of the following.

LenKa [72]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Now from the question;

(a) The distance from (4, -7, 6) to the xy-plane

The xy-plane is the point where z is 0. i.e

xy-plane = (4, -7, 0).

Therefore, the distance d is from (4, -7, 6) to (4, -7, 0)

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

(b) The distance from (4, -7, 6) to the yz-plane

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from (4, -7, 6) to (0, -7, 6)

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

(c) The distance from (4, -7, 6) to the xz-plane

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

Therefore, the distance d is from (4, -7, 6) to (4, 0, 6)

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

(d) The distance from (4, -7, 6) to the x axis

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from (4, -7, 6) to (4, 0, 0)

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

(e) The distance from (4, -7, 6) to the y axis

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

Therefore, the distance d is from (4, -7, 6) to (0, -7, 0)

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Hence, the distance to the y axis is 7.21 units

(f) The distance from (4, -7, 6) to the z axis

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

Therefore, the distance d is from (4, -7, 6) to (0, 0 6)

d = √[(4 - 0)² + (-7 - (0))² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

5 0

1 year ago