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elena-14-01-66 [18.8K]
2 years ago
7

Jennifer is on a trip and travels a distance of 150 miles. she spends some of her time walking, and some of her time travelling

by train. if she spends w hours walking and t hours travelling by train, what is the meaning of 3w in the equation below? 50t + 3w =150
Mathematics
1 answer:
Blababa [14]2 years ago
6 0
3w meant that she took 3 hours walking along the trip.
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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
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Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

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2 years ago
In a factory, two thirds of the floor are is taken up by the production line.Out of the remaining floor area,three fifths is tak
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Answer:the floor area of the production line is 20000 m^2

Step-by-step explanation:

Let x represent the total area of the factory.

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The remaining floor area would be

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Out of the remaining floor area,three fifths is taken up by the office space. This means that the area taken up by the office space would be 3/5 × x/3 = x/5 m^2

The remaining area would be

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The floor area of the production line would be

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How much would Carol have to invest today at 6.2% compounded annually to have $4600 for a vacation to China in two years?
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\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4600\\
P=\textit{original amount deposited}\\
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n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
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t=years\to &2
\end{cases}
\\\\\\
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