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Ksivusya [100]
2 years ago
9

Makayla is taking a math course and is working with the perimeter of rectangles. She knows the perimeter and length of her recta

ngle but wants to solve for the width. Rearrange the following equation for W, where P is the perimeter, L is the length, and W is the width of the rectangle. P = 2L + 2W.
A. W = 2p − 2l
B. W = p/ 2-2 times l
C. W = the quantity p + 2 times l/2
D. W = 2p + 2l
Mathematics
1 answer:
jeka942 years ago
5 0

Answer:

  W=\dfrac{P}{2}-L

Step-by-step explanation:

  P=2L+2W \qquad\text{given}\\\\P-2L=2W \qquad\text{subtract $2L$}\\\\\dfrac{P-2L}{2}=W \qquad\text{divide by 2}\\\\W=\dfrac{P}{2}-L \qquad\text{carry out the division}

This formula does not seem to be among the answer choices.

  W = (P/2) -L

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The total revenue that is gained from the sales of the cakes is determined by multiplying the number of cakes by the price. If we let x be the number of $1 that should be deducted from the price and y be the total revenue,
                               y = (25 - x)(100 + 5x)
Simplifying, 
                              y = 2500 + 25x - 5x²
We get the value of x that will give us the maximum revenue by differentiating the equation and equating the differential to zero.
                             dy/dx = 0 = 25 - 10x
The value of x is 2.5. 
 The price of the cake should be 25 - 2.5 = 22.5. 
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7 0
2 years ago
Is AB parallel to Bo? Explain.
Svetradugi [14.3K]

Answer:

AB parallel to CD because both lines have a slope of

of 4/3

Step-by-step explanation:

The question is not complete, there is no graph.

A graph for the question is attached below.

From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).

Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

(x_1,y_1)\ asnd\ (x_2,y_2).\ The\ slope \ is\ given\ as:\\\\Slope(m)=\frac{y_2-y_1}{x_2-x_1}

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-3)}{0-(-3)}=\frac{1+3}{0+3}=\frac{4}{3}

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-5)}{3-0}=\frac{-1+5}{3}=\frac{4}{3}

Therefore AB parallel to CD because both lines have a slope of

of 4/3

7 0
2 years ago
The phone company charges a flat rate of $25 per month. In addition they charge $0.05 for each minute of service Which equation
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Answer:

c= 25+0.05m

Step-by-step explanation:

Given that,

The phone company charges a flat rate of $25 per month. In addition they charge $0.05 for each minute of service.

$25 is fixed here and charge $0.05 for each minute of service.

We need to find the equation that can be used to find the monthly charge based upon the number of minutes (m) of service each month.

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2 years ago
What are the measures of Arc J K and ∠KIJ?
expeople1 [14]

Answer:

104 and 52

Step-by-step explanation:

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7 0
2 years ago
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Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
2 years ago
Read 2 more answers
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