Francesca spent 25 minutes on the internet yesterday if this is 5/6 of the time she spent on the computer,how long did she spend
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I suppose
The vectors that span form a basis for
if they are (1) linearly independent and (2) any vector in
can be expressed as a linear combination of those vectors (i.e. they span
).
- Independence:
Compute the Wronskian determinant:
The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of is 3.
- Span:
Write an arbitrary vector in as
. Then the given vectors span
if there is always a choice of scalars
such that
which is equivalent to the system
The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives
so the vectors do span .
The vectors comprising form a basis for it because they are linearly independent.
Use this property of logarithms:
Your equation transforms into:
Now, you have to apply the definition of a logarithm to express the equation in exponential form:
In case you don't remember, this is the definition of a logarithm:
The log is the exponent (y) you have to raise the base (b) to in order to get the power (x).
Finally, solve the rational equation:
The correct answer is d.
Your equation transforms into:
Now, you have to apply the definition of a logarithm to express the equation in exponential form:
In case you don't remember, this is the definition of a logarithm:
The log is the exponent (y) you have to raise the base (b) to in order to get the power (x).
Finally, solve the rational equation:
The correct answer is d.