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BigorU [14]
2 years ago
9

Ford Motor Company sells the Fusion SES for $24,400. The Fusion Hybrid sells for $29,975. What is the percentage increase in pri

ce for the Hybrid over the Fusion SES? (Round to tenth.)
Mathematics
2 answers:
Katyanochek1 [597]2 years ago
7 0

Answer:

The percentage increase in price for the Hybrid over the Fusion SES is of 22.84%, which means that the Hybrid is 22.84% more expensive that the Fusion SES.

Rounded to the nearest tenth, it is an increase of about 20%.

Step-by-step explanation:

Fusion SES has a value of $24,400, while the Fusion Hybrid has a value of $29,975. Therefore, the difference between both is of $5,575 (29,975 - 24,400 = 5,575).

In order to know the percentage increase in price for the Hybrid over the Fusion SES, we have to do the following calculation:

5,575 / 24,400 x 100 = Percentage increase in price

0,2284 x 100 = 22.84

The percentage increase in price for the Hybrid over the Fusion SES is of 22.84%, which means that the Hybrid is 22.84% more expensive that the Fusion SES.

Round to the nearest tenth, it is an increase of about 20%.

Lubov Fominskaja [6]2 years ago
6 0
Percent increase is:
Change/original * 100
(29975-24400)/24400
5575/24400= .228 * 100=
22.8%
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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
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