Given that the angle measure 20 and the side opposite to that angle measures 10 cm, suppose this is the height of the triangle, the hypotenuse
Such that
sin theta=opposite/hypotenuse
opposite=a=10 cm
sin 20=10/h
multiplying both sides by h we get
hsin20=10
hence;
h=10/sin20
h=29.24 cm
h=29.2 cm
Answer:
$713.8
Step-by-step explanation:
14%of 860 = 120.4
3% of 860 = 25.8
so, subtract the sum of the above 2 values from 860.
860 - (120.4+25.8) = 860-146.2 = 713.8
Hope this helps
First month she payed 1451 dollars
Second month she payed 1/3 of that, which is:
1451/3 = 483.66
Third month she payed 1/3 of 483.66 because as text says, every next month she pays 1/3 of previous month payed amount.
483.66/3 = 161.22
Forth month she payed
161.22/3 = 53.74
In total she payed:
$2149.62 - B.
hope this helps :)
Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>
Step-by-step explanation:
Given the function j(x) = 11.6
and k(x) =
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6
and k(x) =
are inverse functions.