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Dmitry_Shevchenko [17]
2 years ago
14

A random sample of 10 chocolate energy bars of a certain brand has, on average, 230 calories per bar, with a standard deviation

of 15 calories. Construct a 99% confidence interval for the true mean calorie con- tent of this brand of energy bar. Assume that the dis- tribution of the calorie content is approximately nor- mal.
Mathematics
1 answer:
Troyanec [42]2 years ago
5 0

Answer:

The confidence interval for the true mean calorie content is

215

Step-by-step explanation:

In this problem we know the mean and standard deviation fo the sample, so we can compute the CI like this:

\bar{x}-t*s/\sqrt{n}< \mu

We need to determine t for 10-1=9 degrees of freedom and 99% confidence level. We look up in the t-table and the value for t is 3.2498.

Then we can calculate the limits of the CI:

\bar{x}-t*s/\sqrt{n}< \mu

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Romashka-Z-Leto [24]

Answer:

\dfrac{15}{2}

Step-by-step explanation:

The diagram shows right triangle with hypotenuse of 15 units and angle of 30°. This angle is opposite to the leg with length of x units.

In the right triangle, the leg opposite to the 30° angle is half of the hypotenuse, so

x=\dfrac{15}{2}\ units

4 0
1 year ago
Find the P​-value in a test of the claim that the mean IQ score of acupuncturists is equal to​ 100, given that the test statisti
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Answer:

P-value = 0.0455

Step-by-step explanation:

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1 year ago
A sign is hammered into a tree 2m from the trees base. if the tree is 10m tall and elongates 1m each year, how high will the sig
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6 0
2 years ago
Sienna is solving the quadratic equation by completing the square. 3x2 + 9x – 4 = 0 3x2 + 9x = 4 A(x2 + 3x) = 4 What is the valu
bogdanovich [222]

Answer:

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3 0
1 year ago
Read 2 more answers
According to chebyshev's theorem, at least what percent of the observations lie within plus and minus 1.75 standard deviations o
Alborosie
Chebyshev's theorem in statistics states that for many probability distributions, no more than 1/k² of measured values will be k standard deviations away from the mean.

Because the area under the probability distribution curve is equal to 1, Chebyshev's theorem means that the shaded area shown in the figure is equal to 1 - 1/k².

When k = 1.75, the shaded area is
1 - 1/1.75² = 0.7635 = 67.35%

Therefore the percent of the area within +/- 1.75 standard deviations from the mean is
67.35/2 = 33.7%, which is at least 33% of the observations.

Answer:
According to the Chebyshev theorem, at least 33% of the observations lie within +/- standard deviations from the mean.

4 0
1 year ago
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