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____ [38]
2 years ago
8

The coordinates of △ABC are A(−11,7), B(−5,−3), C(−2,3). After a dilation, the coordinates are A'(22,−14), B'(10,6), C'(4,−6). F

ind the scale factor.
Mathematics
1 answer:
otez555 [7]2 years ago
7 0

Answer:

-2

Step-by-step explanation:

Before a dilation you have the point (x,y).

After a dilation of a scale factor of r you have (r*x,r*y).

Let's look at one pair of corresponding points.

A(-11,7)  and A'(22,-14)

We need to figure out what we can multiply to -11 to get 22.

We need to figure out what we can multiply to 7 to get -14.

Hopefully it is the same number or this isn't a dilation.

So to get from pre-image to image you need to multiply by -2 because -11*-2=22 and 7*-2=-14.

The scale factor is -2.

The dilation is this: (x,y)->(-2x,-2y)

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Solve for x 3x−91>−87 OR 21x−17>25
klasskru [66]

Answer:

  x > 4/3

Step-by-step explanation:

The first inequality can be solved this way ...

  3x -91 > -87

  3x > 4 . . . . . . . add 91

  x > 4/3 . . . . . . divide by 3

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The second inequality has solution ...

  21x -17 > 25

  21x > 42 . . . . . . add 17

  x > 2 . . . . . . . . . divide by 21

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The solution set is the union of these overlapping solutions, so will be equal to the first solution:

  x > 4/3

5 0
2 years ago
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A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0
2 years ago
Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same sol
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His equation could be written in quadratic form, which is ax^2+bx=c                     


7 0
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enyata [817]

First, Michelle exercises for thirty minutes every day.

If Michelle exercises for 30 minutes for 5 days, this would 30 × 5.

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First find GCF of the numbers:-

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The third choice.
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