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2 years ago

7

Mr. Wells tells his class of 24 that when they completed the assignment, they may play online math games. At the end of class, 4

0% of the class is playing online math games. Approximately how many students still need to complete their assignmnet?

1 answer:

QveST [7]2 years ago

3 0

Hello there! Your answer is approximately 14 students.

To solve this question, you want to start by finding 40% of 24. To do this, convert 40% into a decimal (divide by 100) and multiply by 24.

24 x 0.40 = 9.6.

But - you can't have 9.6 of a student. So, we round up to 10.

Note that the question asks how many students <em>still need to complete</em> their assignment, meaning we are looking for the ones that haven't finished. We found the amount for students that <em>have</em> finished, so subtract that from the total to see approximately how many still have to finish.

24 - 10 = 14

So, this means approximately 14 students still need to complete their assignment.

I hope I could help you, have a great rest of your day! :D

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Citrus2011 [14]

Answer:

6 times

Step-by-step explanation:

There are two events here:

1. Probability to hit snooze button= P(A) = 20%. Also mean P(A') = 80%

2. The probability to miss the bus= B

If Josiah hits the snooze button (A is happen), he misses the bus(B) 25% of the time. It mean P(B | A) = 25%

If Josiah doesn't hit the snooze button (A didn't happen), he won't miss the bus. It mean P (B | A') = 0%

If alarm woke Josiah 120 times , expected times that Josiah miss the bus will be:

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2 years ago

GaryK [48]

Diagram for part A and part C is attached herewith.

Solving for part B:-

Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that it bisects AC into two equal parts AB and BC. Now we have two triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property), and BA=BC (given in the question). Using SSS congruency of triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude ∡OBA=∡OBC (=90°). Hence OB⊥AC i.e. OB is perpendicular to AC.

Solving for part D:-

Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that AB is perpendicular to AC i.e. ∡B=90°. Now we have two Right triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property). Using HL congruency of right triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude BA=BC. Hence OB bisects AC into AB=BC.

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2 years ago

The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (−1, 8). The ball reach

sukhopar [10]

Answer:

The required equation is:

$y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4$

Explanation:

Let us assume that the hole is at y = 0m, with x as the time.

From the question we have (-1s, 8m) as the vertex (here x being the time variable is supposed to be in seconds and y being the distance variable is supposed to be in meters)

At x = 1s, the ball gets to the hole, therefore we have point (1s, 0m)

We know that the vertex of the parabola y = ax² + bx + c is at

$x =\frac{-b}{2a}$

therefore we have:

$-1 = \frac{-b}{2a}$

We then have the following equations:

$8 = a\times -1^2 + b\times -1 + c$

$0 = a\times -1^2 + b\times 1 + c$

$-1 = \frac{-b}{2a}$

From the 3rd equation we have

1 X 2a = b.

Therefore we have:

$8 = a\times -1^2 - 1\times 2a\times1 + c$

$0 = a\times 1^2 + 1 \times2a\times 1 + c$

We can simplify both equations and get:

$8 = a\times( -1^2 - 2s^2) + c = -a\times 3^2 + c$

$0 = a\times(1^2 + 2^2) + c = a\times 3^2 + c$

The first equation now becomes:

$8 = -a\times 3 - a\times 3 = -a\times 6$

$a = frac{8}{-6} = -\frac{4}{3}$

With a, we can find the values of c and b.

$c = -a\times3 = -(-\frac{4}{3})*3 = 4$

$b = 1\times 2a = 1\times 2(-\frac{4}{3})= -\frac{8}{3}$

Then the equation is:

$y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4$

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Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) $x = 6.2\times 12$ Given.

2) $x = \left(6+0.2\right)\times 12$ Definition of addition.

3) $x = 6\times 12 + 0.2\times 12$ Distributive property.

4) $x = 72 + \frac{2}{10}\times 12$ Definitions of multiplication and decimal number.

5) $x = 72 +[2\cdot (10)^{-1}]\cdot 12$ Definition of division/Associative property.

6) $x = 72 + [2\cdot 12]\cdot (10)^{-1}$ Associative property.

7) $x = 72 + 24\cdot 10^{-1}$ Definition of multiplication.

8) $x = 72 + \frac{24}{10}$ Definition of divsion.

9) $x = 72 + 2.4$ Defintion of decimal number.

10) $x = 74.4$ Definition of addition/Result

Natalia's work is wrong.

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