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frosja888 [35]
2 years ago
7

Mr. Wells tells his class of 24 that when they completed the assignment, they may play online math games. At the end of class, 4

0% of the class is playing online math games. Approximately how many students still need to complete their assignmnet?
Mathematics
1 answer:
QveST [7]2 years ago
3 0

Hello there! Your answer is approximately 14 students.

To solve this question, you want to start by finding 40% of 24. To do this, convert 40% into a decimal (divide by 100) and multiply by 24.

24 x 0.40 = 9.6.

But - you can't have 9.6 of a student. So, we round up to 10.

Note that the question asks how many students <em>still need to complete</em> their assignment, meaning we are looking for the ones that haven't finished. We found the amount for students that <em>have</em> finished, so subtract that from the total to see approximately how many still have to finish.

24 - 10 = 14

So, this means approximately 14 students still need to complete their assignment.

I hope I could help you, have a great rest of your day! :D

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Find the volume of a pyramid with a square base, where the perimeter of the base is 5.1 in 5.1 in and the height of the pyramid
lana66690 [7]

Step-by-step explanation:

PARA ENCONTRAR CUÁNTO MIDE CAD LADO SE DIVIDE EL PERÍMETRO

ENTRE 4 LADOS

l = 1.28 in

LOEGO ENCUENTRAS EL RADIO DE LA PIRÁMIDE

<em>r</em> = 2.55 in

USANDO LA FÓRMULA

V = 4(1.28 in)(2.55 in)(2.7 in)/6 = 5.9 in^{3}

6 0
2 years ago
terrence made a sphere out of modeling clay. the sphere had a radius of 2 inches. approximately how much modeling clay did terre
navik [9.2K]

Amount of clay used = volume of the sphere

It is given that the radius of the sphere is 2 inches.

Volume of the sphere = \frac{4}{3} \pi r^{3}

=\frac{4}{3} \pi (2^{3} )

=\frac{4}{3} \pi (8)

=\frac{32}{3} \pi

Hence, the amount of modeling clay Terrence used =\frac{32}{3} \pi cubic inches.


5 0
1 year ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
2 years ago
At a large company, employees can take a course to become certified to perform certain tasks. There is an exam at the end of the
WINSTONCH [101]

Answer:

A Type II error is when the null hypothesis is failed to be rejected even when the alternative hypothesis is true.

In this case, it would represent that the new program really increases the pass rate, but the sample taken is not enough statistical evidence to prove it. Then, the null hypothesis is not rejected.

The consequence is that the new method would be discarded (or changed) eventhough it is a real improvement.

Step-by-step explanation:

5 0
1 year ago
Which situation involves descriptive statistics?
zmey [24]
They all involve descriptive statistics.
8 0
1 year ago
Read 2 more answers
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