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kifflom [539]
2 years ago
8

A class in advanced physics is composed of 10 juniors, 30 seniors, and 10 graduate students. the final grades show that 3 of the

juniors, 10 of the seniors, and 5 of the graduate students received an a for the course. if a student is chosen at random from this class and is found to have earned an a, what is the probability that he or she is a senior?
Mathematics
1 answer:
const2013 [10]2 years ago
5 0

Solution: We are given:

Total students = 10 + 30 + 10 =50

Number of students who received A grade = 3 + 10 + 5 = 18

Number of senior student's who received A grade is = 10

Let A be the event that the student is senior and B be the event that he or she earned an A. Then,

P(A \cap B)=\frac{10}{50}

P(B) = \frac{18}{50}

Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:

P(A|B) = \frac{P(A \cap B}{P(B)}

                 =\frac{\frac{10}{50} }{\frac{18}{50} }

                 =\frac{10}{18}=\frac{5}{9} =0.556


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Answer:

Step-by-step explanation:

We'll just work on solving both so you can see what's involved in solving an absolute value equation. Because an absolute value is a distance, we can have that distance being both to the right on the number line of the number in question or to the left. For example, from 2 on the number line, the numbers that are 5 units away are 7 and -3. Using that logic, we will simplify the equation down so we can set up the 2 basic equations needed to solve for x.

If  3-2|.5x+1.5|=2 then

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Now we can set up the 2 main equations for this which are

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Knowing that an absolute value will never equal a negative number (because absolute values are distances and distances will NEVER be negative), once we remove the absolute value signs we can in fact state that the expression on the left can be equal to a negative number on the right, like in the second equation above.

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