The experiment is comparing veterinary and pets, and that pets are more vulnerable to cardiovascular disease than its counterpart.
Hypothesis is a education claim that is based on observation. Moreover, it is tested to check whether it is supported by the reality of the situation or not. Now, the hypothesis for this can be: there is a significant difference between the blood cholesterol levels among dogs and humans and how it affects cardiovascular disease.
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From 0g to 494.7g are rejected as well as those heavier than 505.3grams.
You calculate this by subtracting and adding 5.3 to 500
        
                    
             
        
        
        
Answer:
The fraction of the students who failed to went partying = 
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students 
⇒ No. of students partied before the exam =  × 100
 × 100
⇒ No. of students partied before the exam =  20
No. of students who not partied before the exam = 
Thus the fraction of the students who failed to went partying = 
 
        
             
        
        
        
Answer:
For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
Step-by-step explanation:
Notation
 represent the sample mean for the sample
 represent the sample mean for the sample  
 population mean (variable of interest)
 population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size  
Solution to the problem
The confidence interval for the mean is given by the following formula:
 (1)
   (1)
In order to calculate the mean and the sample deviation we can use the following formulas:  
 (2)
 (2)  
 (3)
 (3)  
In order to calculate the critical value  we need to find first the degrees of freedom, given by:
 we need to find first the degrees of freedom, given by:
 
For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
 
        
             
        
        
        
Let us say that the procedure of completely filling up the
pool with water is called “1 job”. Therefore the rates of the equipment in
doing the job would be:
<span>Rate of handheld hose = 1 job / 8 minutes                  ---> 1</span>
<span>Rate of lawn sprinkler = r                                             --->
2</span>
<span>Rate of the two combines = 1 job/ 5 minutes               ---> 3</span>
So we are to find the equation to use, in this case, we
simply have to add equations 1 and 2 to get 3:
1 / 8 + r = 1 / 5
Multiplying both sides by 5:
<span>(5 / 8) + 5 r = 1                                                               --->
ANSWER</span>