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4vir4ik [10]
2 years ago
9

It takes 8 minutes for Byron to fill the kiddie pool in the backyard using only a handheld hose. When his younger sister is impa

tient, Byron also uses the lawn sprinkler to add water to the pool so it is filled more quickly. If the hose and sprinkler are used together, it takes 5 minutes to fill the pool. Which equation can be used to determine r, the rate in parts per minute, at which the lawn sprinkler would fill the pool if used alone?
 + 5r = 8
 + 5r = 1
5() = r 
 = 5r
Mathematics
2 answers:
andreyandreev [35.5K]2 years ago
8 0

Let us say that the procedure of completely filling up the pool with water is called “1 job”. Therefore the rates of the equipment in doing the job would be:

<span>Rate of handheld hose = 1 job / 8 minutes                  ---> 1</span>

<span>Rate of lawn sprinkler = r                                             ---> 2</span>

<span>Rate of the two combines = 1 job/ 5 minutes               ---> 3</span>

So we are to find the equation to use, in this case, we simply have to add equations 1 and 2 to get 3:

1 / 8 + r = 1 / 5

Multiplying both sides by 5:

<span>(5 / 8) + 5 r = 1                                                               ---> ANSWER</span>

mojhsa [17]2 years ago
4 0

Answer:

5/8 + 5r = 1

Step-by-step explanation:

Right on edge!

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Answer: 36 years

Step-by-step explanation:

Exponential equation to represent growth:-

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Given : A rare coin appreciates at a rate of 5.2% a year. If the initial value of the coin is $500.

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The amount after t years:

y=500(1.052)^t

Inequality for value cross $3,000 mark:

3000

Divide both sides by 500

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Taking log on both sides , we get

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Answer:

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6 0
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Shishir bought 4000 orange at 70 paisa each. But 400 of them were rotten. He sold 2000 oranges at 90 paisa each.If he plans to m
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Answer:

He needs to sell the rest of the oranges at 75 paisa each.

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Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

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Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

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The number of oranges now Shishir have:

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He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

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Therefore, the cost of one orange is:

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1 orange = 1200/1600 rupees

1 orange = 0.75 rupees

Hence, he needs to sell the rest of the oranges at 75 paisa each.

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23-11=12
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2 years ago
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