A. (−3, 3)
<span>3x – 4y = 21
</span>3(-3) - 4(3) = 21
-21 = 21 >>>>> not equal
B. (−1, −6)
<span>3(-1) - 4(-6) = 21
</span>21 = 21 >>>>>>>>>>Equal
C. (7, 0)
<span>3(7) - 4(0) = 21
</span>21 = 21>>>>>>>>>>equal
D. (11, 3)
<span>3(11) - 4(3) = 21
</span>21 = 21 >>>>>>>>>equal
Answer:
The correct option is second one i.e 24 units.
Therefore the height of the triangle is
Step-by-step explanation:
Given:
An equilateral triangle has all sides equal.
ΔMNO is an Equilateral Triangle with sides measuring,
NR is perpendicular bisector to MO such that
.NR ⊥ Bisector.
To Find:
Height of the triangle = NR = ?
Solution :
Now we have a right angled triangle NRM at ∠R =90°,
So by applying Pythagoras theorem we get
Substituting the values we get
Therefore the height of the triangle is
The line x = 0 is perpendicular to the line y = -3:
Correct. Any horizontal line (y = a) and any vertical line (x = b) intersect at some point and are perpendicular.
All lines that are parallel to the y-axis are vertical lines:
Correct. The y-axis is a vertical line, so any lines that are parallel to it must also be vertical.
All lines that are perpendicular to the x-axis have a slope of 0.
Incorrect. Lines that have a slope of 0 are horizontal, and the x-axis is horizontal as well. Any lines with a slope of 0 are <em>parallel </em>to the x-axis, not perpendicular to it.
The equation of the line parallel to the x-axis that passes through the point (2, 6) is x = 2.
Incorrect. x = 2 is a vertical line, and vertical lines cannot be parallel to the horizontal x-axis. x = 2 is perpendicular to the x-axis, however.
The equation of the line perpendicular to the y-axis that passes through the point (-5, 1) is y = 1.
Correct. The line y = 1 is horizontal, and the y-axis is a vertical line. Because the line y = 1 crosses the y-axis, the lines are perpendicular.
It increases at T because the behavior increased its speed
