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Harman [31]
2 years ago
8

Which statements are true Select three options.

Mathematics
1 answer:
BARSIC [14]2 years ago
4 0

The line x = 0 is perpendicular to the line y = -3:

Correct. Any horizontal line (y = a) and any vertical line (x = b) intersect at some point and are perpendicular.

All lines that are parallel to the y-axis are vertical lines:

Correct. The y-axis is a vertical line, so any lines that are parallel to it must also be vertical.

All lines that are perpendicular to the x-axis have a slope of 0.

Incorrect. Lines that have a slope of 0 are horizontal, and the x-axis is horizontal as well. Any lines with a slope of 0 are <em>parallel </em>to the x-axis, not perpendicular to it.

The equation of the line parallel to the x-axis that passes through the point (2, 6) is x = 2.

Incorrect. x = 2 is a vertical line, and vertical lines cannot be parallel to the horizontal x-axis. x = 2 is perpendicular to the x-axis, however.

The equation of the line perpendicular to the y-axis that passes through the point (-5, 1) is y = 1.

Correct. The line y = 1 is horizontal, and the y-axis is a vertical line. Because the line y = 1 crosses the y-axis, the lines are perpendicular.

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2 inches 3 inches Pivot. If 60 lbs. of force must be applied to the valve for it to open, how much upward force must push rod X
tresset_1 [31]

We can solve this problem by stating that the summation of momentums must be zero. That is, the momentum at one end of the pivot must be equal to the momentum at the other end.

Momentum 1 = Momentum 2

Since Momentum is the product of Force and Distance, and with this rule created, we can say that:

F1 * d1 = F2 * d2

Where,

F1 = 60 lbs

d1 = 2 inches from the pivot

F2 = unknown X

d2 = 3 inches from the pivot

Substituting to the equation to find for F2:

60 lbs * 2 inches = F2 * 3 inches

F2 = 40 lbs

 

<span>Therefore 40 lbs of upward force must be pushed to open the valve.</span>

<span>Answer: B</span>

3 0
2 years ago
If HJ= 7x-27 . Find the value of x
Alinara [238K]

we are given

HJ=7x-27

Since, we have to solve for x

so, we will isolate x on anyone side

step-1: Add both sides 27

HJ+27=7x-27+27

HJ+27=7x

step-2: Divide both sides by 7

HJ+27=7x

\frac{HJ+27}{7}= \frac{7x}{7}

now, we can simplify it

\frac{HJ+27}{7}= x

x=\frac{HJ+27}{7}................Answer


7 0
2 years ago
Read 2 more answers
The regular octagon has a perimeter of 122.4 cm. Which statements about the octagon are true? Select two options. The length of
KATRIN_1 [288]

The correct answers on edge are C and E

6 0
2 years ago
Read 2 more answers
A store had 4 boxes of video Games.How many days would it take to sell the games if each day they sold one fifth
Korvikt [17]
The answer would be 20 days.
8 0
2 years ago
Read 2 more answers
Can someone help please
riadik2000 [5.3K]

Answer:

  62 Sunday papers were sold

Step-by-step explanation:

Let x represent the number of Sunday papers sold. Then half that many, or x/2, is the number of Friday papers sold. The total revenue from the sales is the sum of products of quantity and price:

  1.50 · x + 0.75 · (x/2) = 116.25

Multiplying by 2, this becomes ...

  3.00x +0.75x = 232.50

  3.75x = 232.50

Dividing by the coefficient of x gives ...

  232.50/3.75 = x = 62

The number of Sunday newspapers sold is 62.

6 0
2 years ago
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