Answer:
0
Step-by-step explanation:
We have the fraction 
Step 1. Use LCM of the fraction, (2m+3)(2m-3), to simplify the fraction:
![\frac{(2m-3)(2m)-(2m+3)(2m)}{(2m+3)(2m-3)} =\frac{2m^2-6m-[2m^2+6m]}{(2m+3)(2m-3)} =\frac{2m^2-6m-2m^2-6m}{(2m+3)(2m-3)} =\frac{-12m}{(2m+3)(2m-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B%282m-3%29%282m%29-%282m%2B3%29%282m%29%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-%5B2m%5E2%2B6m%5D%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-2m%5E2-6m%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B-12m%7D%7B%282m%2B3%29%282m-3%29%7D)
Step 2. Equate the resulting fraction to zero and solve for 
:
![-12m=0[(2m+3)(2m-3)]](https://tex.z-dn.net/?f=-12m%3D0%5B%282m%2B3%29%282m-3%29%5D)
Step 3. Replace the value in the original equation and check if it holds:
Since ,
Since the only solution of the equation holds, the equation bellow doesn't have any extraneous solution
Step-by-step explanation:
If a triangle is rotated 90° about the origin.
The rule that describes the transformation is
(x, y) → (–y, x)
Given:
Joanna :
works 14 hrs a week more than her line workers.
gets paid 6.50 more per hour than her line workers.
Line workers: h = hours per week ; d = dollars per hour.
Line worker = Dollar per hour * number of hours.
Joanna = (Dollar per hour + 6.50)(number of hours + 14 hours)
Line worker:
$576 = d * 36 hours
$576/36 = d
$16 = d hourly rate of line worker.
Joanna:
$16 + 6.50 = $22.50 hourly rate
36hrs + 14hrs = 50 hours per week.
Weekly pay of Joanna: $22.50 * 50 = $1,125
Answer:
(B)93
Explanation:
Since we are using a fixed-order-interval model,
The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand
Where:
d=weekly demand
OI=Order Interval
LT=Lead Time
z=Standard Deviation of Desired Service Level
=Standard Deviation of weekly Demand
A= Amount at Hand
![[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43](https://tex.z-dn.net/?f=%20%5B30%283%20%2B%201%29%5D%20%2B%20%5B1.964%2A4%2A%5Csqrt%7B3%20%2B%201%7D%20-%2043)
