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scoundrel [369]
2 years ago
15

2. Santiago wants the lateral surfaces of the

Mathematics
1 answer:
MakcuM [25]2 years ago
8 0

Answer:

262 square feet  of the ramp will be painted red.

Step-by-step explanation:

The lateral surface is surface area of the sides of the ramp without including the top and bottom faces

The ramp shown has three surfaces

The 2 sides are triangles with length 20 and height 8.5

The back is a rectangle shape with length 12 and height 8.5

Step 1: Finding the  Area of triangle

The area of the triangle  = \frac{1}{2} length \times height

The area of the triangle  = \frac{1}{2} (20 \times 8.5)

The area of the triangle  = \frac{170}{2}    

The area of the triangle = 85 square feet

Area of 2 triangles = 85 \times 2  =  170

Step 2: Finding the  Area of Rectangle

Area of rectangle = length  \times height

so,

Area of back rectangle = 12  \times 8.5 = 102  square feet

Step 3: Finding the total lateral surface area

Total Lateral Surface Area

= Area of triangle + Area of Rectangle

= 272 square feet

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To solve this problem you must follow the proccedure shown below:

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2 years ago
Please please please help me
Gwar [14]
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2 years ago
A Car is moving on a straight road with velocity 30m/s and is speeding up at constant rate and reaches a velocity of 90m/s. What
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Answer:

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Triangles E F G and E prime F prime G prime are shown. Angles F E G and F prime E prime G prime are 72 degrees. Angles E F G and
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Answer:

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Step-by-step explanation:

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2 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

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If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
2 years ago
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