Answer:
The given variable is a continuous variable.
Step-by-step explanation:
We are given the following variable in the question:
Variable: "The volume of cola in a can is 11.1 oz"
Discrete variable:
- These can be expressed in whole numbers and cannot take value in decimals
- They are counted not measured.
- They cannot take any value within an interval.
Continuous Variable:
- These can be expressed in decimal numbers.
- They are measured not counted.
- They can take any value within an interval.
Thus, the given variable which is volume is measured and can tale any value within an interval.
Thus, it is a continuous variable.
Okay, let's do this~
we want v isolated on one side so let's bring w over through subtraction
now we have 5/9v=z-w
now, to get rid of that fraction attached to v, we will multiply it's reciprocal on both sides.
*the reciprocal of 5/9 is 9/5
(5/9) x (9/5) cancel each other leaving v isolated to the left
the other side should look like this 9/5(z-w)
now we put both parts together to end up with:
v= 9/5(z-w)
there you go! :D
So average is of the first 6 tests is 82 well that means
(test1 + test2+ test3+ test4 + test5+test6)/6 = 82
so now let do some cross multiplliying
test1 + test2 + test3 + test 4 + test5 +test6 = 82*6
test1 + test2 + test3 + test 4 + test5 +test6 = 492
now lets see if we can find that 7th test score
(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5
So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.
(492 + test7 )/7 = 80.5
test7 = (80.5*7)-492 = 71.5
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
