Answer:
cl + 1/(N+1)
Step-by-step explanation:
If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl
And we know that the (N+1)th harmonic number can be found by doing
1+1/2+1/3+1/4+...+1/N+1/(N+1)
=cl + 1/(N+1)
The (N+1)th harmonic number is cl + 1/(N+1) given that the Nth term is cl
Other way to see the answers:
Maybe you want to write it as a single fraction so you have
[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)
$5 + $1.99 = 6.99
I hope this helps! Have a great day! :-)
Answer:
I don't understand wat u said
Answer:
Step-by-step explanation:
If the smallest number is 'x', then the other number = x +1
x*(x+1)= 420
Use distributive property
x*x + x*1 = 420
x² + x - 420 =0 ------> this is the required quadratic equation.