Since the number of bird decreases 3% per year then for year 1 there will be 29 100 birds left. This value is 97% of 30000. From this the number of birds for year 1 is N = 30000(1-0.03)

A. N = 30,000 $(1-0.03)^{2}$

B. To solve this we use the equation we established in letter A. We get the answer by substituting T with 20. N = 16,000. <span />

8 0

2 years ago

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There are 40 girls and 32 boys who want to participate in the relay race. If each team must have the same number of girls and bo

xxMikexx [17]

Answer:

8 teams

5 girls and 4 boys

Step-by-step explanation:

To determine how many teams we can have , we need to determine the greatest common factor.

girls:40 = 5*8

boys:32 = 4*8

The greatest common factor is 8

So we will have 8 teams

There will be 5 girls and 4 boys on each team

6 0

2 years ago

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

LUCKY_DIMON [66]

Answer:

y2 = C1xe^(4x)

Step-by-step explanation:

Given that y1 = e^(4x) is a solution to the differential equation

y'' - 8y' + 16y = 0

We want to find the second solution y2 of the equation using the method of reduction of order.

Let

y2 = uy1

Because y2 is a solution to the differential equation, it satisfies

y2'' - 8y2' + 16y2 = 0

y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)

Using these,

y2'' - 8y2' + 16y2 =

[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0

u''e^(4x) = 0

Let w = u', then w' = u''

w'e^(4x) = 0

w' = 0

Integrating this, we have

w = C1

But w = u'

u' = C1

Integrating again, we have

u = C1x

But y2 = ue^(4x)

y2 = C1xe^(4x)

And this is the second solution

5 0

2 years ago