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2 years ago

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Sofia measures the length of her car as 16 feet. What is the greatest possible error? ______ feet What is the margin of error? _

_____ to ______ feet

1 answer:

Genrish500 [490]2 years ago

3 0

Answer:

Sofia measures the length of her car as 16 feet.

What is the greatest possible error?

<h2> ⇒ 0.5 feet </h2>

What is the margin of error?

<h2> ⇒ 15.5 TO ⇒ 16.5 feet</h2>

Step-by-step explanation:

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Write the number described by 1 ten 16 ones.

Alexxx [7]

1 ten 16 ones=1*10+16*1=10+16=26

Hope this helps!

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1 year ago

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The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.512.512, point, 5 years; the stan

zaharov [31]

This question was not written properly

Complete Question

The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.5 years; the standard deviation is 2.4 years. Use the empirical rule (68-95-99.7\%)(68−95−99.7%) to estimate the probability of a lion living between 5.3 to 10. 1 years.

Answer:

Thehe probability of a lion living between 5.3 to 10. 1 years is 0.1585

Step-by-step explanation:

The empirical rule formula states that:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

3) 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean is given in the question as: 12.5

Standard deviation : 2.4 years

We start by applying the first rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

12.5 -2.4

= 10.1

We apply the second rule

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

μ – 2σ

12.5 - 2 × 2.4

12.5 - 4.8

= 7.7

We apply the third rule

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

μ - 3σ

= 12.5 - 3(2.4)

= 12.5 - 7.2

= 5.3

From the above calculation , we can see that

5.3 years corresponds to one side of 99.7%

Hence,

100 - 99.7%/2 = 0.3%/2

= 0.15%

And 10.1 years corresponds to one side of 68%

Hence

100 - 68%/2 = 32%/2 = 16%

So,the percentage of a lion living between 5.3 to 10. 1 years is calculated as 16% - 0.15%

= 15.85%

Therefore, the probability of a lion living between 5.3 to 10. 1 years

is converted to decimal =

= 15.85/ 100

= 0.1585

8 0

2 years ago

Kendra has a bowl containing 10 blue marbles, 15 yellow marbles, 5 green marbles, and 6 red marbles of the same size. She will r

Mice21 [21]

Given:
10 blue marbles ; 15 yellow marbles, 5 green marbles, 6 red marbles
A total of 36 marbles.

Probabilities:
1st marble: red = 6/36
2nd marble: yellow = 15/35

6/36 * 15/35 = 6*15 / 36*35 = 90/1260 = 1/14

The probability that Kendra will draw a red marble and then a yellow marble is 1/14.

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2 years ago

The scores of eighth-grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.

Anna11 [10]

Approximately 68% of a normal distribution lies within one standard deviation of the mean, so this corresponds to students with scores between (57.5 - 6.5, 57.5 + 6.5) = (51, 64)

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2 years ago

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Angela has the following coins in her pocket:

GaryK [48]

Answer:

There are 10 different combinations

The list of different combinations is:

(10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

(1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

(10p, 1p)
(10p, 50p)
(10p, 2p)
(10p, 20p)

2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

(1p, 50p)
(1p, 2p)
(1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

(50p, 2p)
(50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

(2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

There are 4 + 3 + 2 + 1 = 10 different combinations

The list of different combinations is:

(10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

(1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

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2 years ago