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Zigmanuir [339]
2 years ago
5

According to chebyshev's theorem, at least what percent of the observations lie within plus and minus 1.75 standard deviations o

f the mean?

Mathematics
1 answer:
Alborosie2 years ago
4 0
Chebyshev's theorem in statistics states that for many probability distributions, no more than 1/k² of measured values will be k standard deviations away from the mean.

Because the area under the probability distribution curve is equal to 1, Chebyshev's theorem means that the shaded area shown in the figure is equal to 1 - 1/k².

When k = 1.75, the shaded area is
1 - 1/1.75² = 0.7635 = 67.35%

Therefore the percent of the area within +/- 1.75 standard deviations from the mean is
67.35/2 = 33.7%, which is at least 33% of the observations.

Answer:
According to the Chebyshev theorem, at least 33% of the observations lie within +/- standard deviations from the mean.

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1. <u>The correct answer is 46%</u>

2. <u>The correct answer is .07</u>

<u>3. The correct answer is (34%,58%)</u>

4. <u>The correct answer is (32%,60%)</u>

Step-by-step explanation:

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

<u>The correct answer is 46%</u>

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

<u>The correct answer is .07</u>

<u>3. </u>Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

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<u>The correct answer is (34%,58%)</u>

4. <u> </u>Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

<u>The correct answer is (32%,60%)</u>

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