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Pavel [41]
1 year ago
9

John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants

to pay back 1.1 times the amount he paid the month before. Explain to John how to represent his first 20 payments in sequence notation. Then explain how to find the sum of his first 20 payments, using complete sentences.
Mathematics
1 answer:
sergeinik [125]1 year ago
8 0
<span>Let a_0 = 100, the first payment. Every subsequent payment is the prior payment, times 1.1. In order to represent that, let a_n be the term in question. The term before it is a_n-1. So a_n = 1.1 * a_n-1. This means that a_19 = 1.1*a_18, a_18 = 1.1*a_17, etc. To find the sum of your first 20 payments, this sum is equal to a_0+a_1+a_2+...+a_19. a_1 = 1.1*a_0, so a_2 = 1.1*(1.1*a_0) = (1.1)^2 * a_0, a_3 = 1.1*a_2 = (1.1)^3*a_3, and so on. So the sum can be reduced to S = a_0 * (1+ 1.1 + 1.1^2 + 1.1^3 + ... + 1.1^19) which is approximately $5727.50</span>
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Answer:

2,7204x 10^9

Step-by-step explanati

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6 0
2 years ago
Which triangle is similar to ΔJKL? ΔJKM, ΔMKL, ΔKML, ΔLJK.
kirill [66]
The answer would be ΔKML because the right angle of ΔKML is in the same place as <span>ΔJKL</span>
7 0
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Product A is and 8oz bottle of cough medication that's sells for $1.36. Product B is 16oz bottle of cough medication that costs
zhenek [66]

Answer:

Product B

Step-by-step explanation:

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4 0
2 years ago
The most popular mathematician in the world is throwing aparty for all of his friends. As a way to kick things off, they decidet
ratelena [41]

Answer:

The no. of possible handshakes takes place are 45.

Step-by-step explanation:

Given : There are 10 people in the party .

To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?

Solution:

We are given that there are 10 people in the party

No. of people involved in one handshake = 2

To find the no. of possible handshakes between 10 people we will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

n = 10

r= 2

Substitute the values in the formula

^{10}C_{2}=\frac{10!}{2!(10-2)!}

^{10}C_{2}=\frac{10!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 \times 8!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 }{2 \times 1}

^{10}C_{2}=45

No. of possible handshakes are 45

Hence The no. of possible handshakes takes place are 45.

4 0
1 year ago
The diagram shows the cross section of a cylindrical pipe with water lying in the bottom.
disa [49]
Hey 

So my brother posted this on Yahoo 
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm. 

<span>What you do now is the following: </span>

<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>

<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>

<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>

<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>



<span>b) </span>

<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>

Hoped it Helped
5 0
1 year ago
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