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boyakko [2]
2 years ago
10

In a computer game, A bird flies at a height of 1,281 feet. At the same time of fish swims 282 feet below sea level what is the

difference between the height of the bird and the depth of the fish?
Mathematics
2 answers:
Flauer [41]2 years ago
6 0

1,281 - 1,281 = 0

0 - 282 = - 282

1,281 + 282 = 1,563

ANSWER: 1,563 ft.

Ket [755]2 years ago
5 0

your basically going to add them to see the difference 1,281+282= 1,363

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The dot plots below show rainfall totals in the Highlands and Lowlands areas of a certain region.
Andre45 [30]

Options:

A. Both the Highlands and the Lowlands data points are evenly distributed around the center.

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

C. The Highlands data points are evenly distributed around the center, while the Lowlands data points are clustered toward the left of the plot.

D. The Highlands data points are clustered toward the left of the plot, while the Lowlands data points are evenly distributed.

Answer:

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

Step-by-step Explanation:

From the dot plots displaying rainfall totals for highland and lowland areas as shown in the diagram attached below, we can clearly observe that most of the dots on the plot tend to be more concentrated towards the left of the plot, compared to the concentration of dots toward the right of the plot.

Invariably, we can infer that data points for lowlands and Highlands are clustered toward the left of the plot.

Therefore, the statement that is true, comparing the shapes of the dot plot is B. "Both the Highlands and the Lowlands data points are clustered toward the left of the plot."

7 0
2 years ago
There are 500 employees in a firm, 45% are female. a sample of 60 employees is selected randomly. the probability that the sampl
beks73 [17]

Let X be the number of female employee. Let n be the sample size, p be the probability that selected employee is female.

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For large value of n the Binomial distribution approximates to Normal distribution.

Let p be the proportion of female employee in the given sample.

Then distribution of proportion P is normal with parameters

mean =p and standard deviation = \sqrt{\frac{p(1-p)}{n}}

Here we have p=0.45

So mean = p = 0.45 and

standard deviation = \sqrt{\frac{0.45(1-0.45)}{60}}

standard deviation = 0.0642

Now probability that sample proportions of female lies between 0.40 and 0.55 is

P(0.40 < P < 0.45) = P(\frac{0.40 - 0.45}{0.0642}  < \frac{P-mean}{standard deviation}  < \frac{0.55- 0.45}{0.0642} )

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= P(Z < 1.5576) - P(Z < -0.7788)

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= 0.9406 - 0.2177

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The probability that the sample proportion of females is between 0.40 and 0.55 is 0.7229

6 0
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