Answer:
-1 17/25
Solution with Steps
−65−1225=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-6/5, 12/25) = 25
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(−65×55)−(1225×11)=?
Complete the multiplication and the equation becomes
−3025−1225=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
−30−1225=−4225
This fraction cannot be reduced.
The fraction
−4225
is the same as
−42÷25
Convert to a mixed number using
long division for -42 ÷ 25 = -1R17, so
−4225=−11725
Therefore:
−65−1225=−11725
The correct answers are Losing 12; Winning 15
Explanation:
The ratio of winning to losing is 5: 6 or 5/6. This means for every 5 winning spaces in the wheel there are 6 losing spaces. This ration should be used to complete the values of the table.
1. The first row shows there are 10 winning and you need to calculate the number of losing spaces. The process is shown below.
- Express the ratios using fractions; use x to show the missing value
- Cross multiply to find the value of x
- Solve the equation to find x
- The number of losing is 12 if there are 10 winning spaces
2. The second row shows there are 18 losing spaces, and you need to calculate the number of winning spaces. Repeat the process.
- The number of winning spaces is 15 if there are 18 losing spaces
Answer:
$1040
Step-by-step explanation:
Let X be the original price.
35% of X = 364
35/100 × X = 364
X = 364 × 100/35
X = 1040
Answer:
47 pounds i think \/'_'\/
Step-by-step explanation:
Answer:
When we do a scale model of something (like a building, a house, or whatever) al the properties of the original thing must also be in the model.
So for example, you want to do a model of a house, and in the backyard of the house there are 4 trees, then in the model of the house you also need to put 4 trees in the backyard (indifferent of the scale of the model).
Then the number of boulders in the really fountain should be the same as the number of boulders in the scale model of the fountain.
