(30 points) The coordinates of the vertices of quadrilateral JKLM are J(−3, 2) , K(3, 5) , L(9, −1) , and M(2, −3) .
Which statement correctly describes whether quadrilateral JKLM is a rhombus?
Quadrilateral JKLM is not a rhombus because there is only one pair of opposite sides that are parallel.
Given:
Area of rectangle = 
Width of the rectangle is equal to the greatest common monomial factor of 
.
To find:
Length and width of the rectangle.
Solution:
Width of the rectangle is equal to the greatest common monomial factor of is
Now,
So, width of the rectangle is 
.
Area of rectangle is
Taking out GCF, we get
We know that, area of a rectangle is the product of its length and width.
Since, width of the rectangle is , therefore length of the rectangle is 
.
Answer:
Annie walked 1 11/12 miles
Step-by-step explanation:
Trail= 4 1/2 miles
Annie ran the first 2/3 miles
Remaining miles= Total miles - Miles covered first
= 4 1/2 - 2/3
= 9/2 - 2/3
= 27-4 / 6
= 23/6 miles
Remaining miles = 23/6 miles
Annie walked for 1/2 of the remaining distance
1/2 of the remaining miles= 1/2 × 23/6
=23 / 12
= 1 11/12
Annie walked 1 11/12 miles
Answer:
Pr(X-Y ≤ 44.2) = 0.5593
Step-by-step explanation:
for a certain breed of terrier
Mean(μ) = 72cm
Standard deviation (σ) = 10cm
n = 64
For a certain breed of poodle
Mean(μ) = 28cm
Standard deviation (σ) = 5cm
n = 100
Let X be the random variable for the height of a certain breed of terrier
Let Y be the random variable for the height of a certain breed of poodle
μx - μy = 72 -28
= 44
σx - σy = √(σx^2/nx + σy^2/ny)
= √10^2/64 + 5^2/100
= √100/64 + 25/100
= √ 1.8125
= 1.346
Using normal distribution,
Z= (X-Y- μx-y) / σx-y
Z= (44.2 - 44) / 1.346
Z= 0.2/1.346
Z= 0.1486
From the Z table, Z = 0.149 = 0.0593
Φ(z) = 0 0593
The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)
Recall that if Z is positive,
Pr(Z≤a) = 0.5 + Φ(z)
Pr(Z ≤ 44.2) = 0.5 + 0.0593
= 0.5593
Therefore,
Pr(X-Y ≤ 44.2) = 0.5593
<span>8x+4y+(-8z^2)+[3z+(-5z)] the answer is D</span>
