Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
285 - 60x ; where x represents the number of driving hours.
285 ⇒ <span>The total distance to the state park.
60x </span>⇒<span> </span><span>The number of miles driven after x hours.
60 </span>⇒<span> </span><span>The number of miles driven after 1 hour.
y = 285 - 6x
y </span>⇒<span> </span><span>The number of miles left to drive each day.</span>
Answer:
1.533333 miles per hour
If It Helped u do mark me as brainliest
