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podryga [215]
1 year ago
11

Jakob wants to invite 20 friends to his birthday, which will cost his parents $250. If he decides to invite 15 friends instead,

how much money will it cost his parents? Alationship is directly proportional.5=245 if he decides to invite 15
Mathematics
2 answers:
Allisa [31]1 year ago
7 0

Answer:

187.5

Step-by-step explanation:

divide 250 by 20 to get unit price per each friend, then multiply by 15 friends and get 187.5

timofeeve [1]1 year ago
4 0

Answer:

$187.50

Step-by-step explanation:

250/25= $12.50 per person

12.5 x 15= $187.50

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1 year ago
Grace drew a triangle. It's sides were 12 mm, 10 mm, and 11 mm. It has one obtuse angle and two acute angles. What triangle did
Mariana [72]

Answer:

Scalene triangle

Step-by-step explanation:

scalene triangle is a triangle where the lengths of all three sides are different, it comprises of both obtuse and acute angles,all giving a sum of 180 degrees

4 0
2 years ago
What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.
Gnesinka [82]
First, we are going to use the law of cosines to find the length of the line segment FH:
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FH=3.2

Next, we are going to use the semi-perimeter formula: s= \frac{GH+FG+FH}{2}
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s= \frac{7.7}{2}
s=3.9

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
A= \sqrt{s(s-GH)(s-FG)(s-FH)}
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3 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
1 year ago
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