solution:
Consider the curve: r(t) = t²i +(int)j + 1/t k
X= t² , y = int ,z = 1/t
Using, x = t², z = 1/t
X = (1/z)²
Xz²= 1
Using y = int, z= 1/t
Y = in│1/z│
Using x = t², y = int
Y = int
= in(√x)
Hence , the required surface are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
Making larger monthly payments than required will pay off a loan faster. Thus, the answer is A.
Answer:
The cost of the gas is £67.81 p
Step-by-step explanation:
Here we have
Initial gas reading = 8247
Final gas reading = 8631
Therefore the total consumed gas is given by
Final gas reading - Initial gas reading → 8631 - 8247 = 384
Since the cost of gas is 11p per unit we have, the total cost of the gas consumed is given by
Cost of consumed gas = Units of gas consumed × Unit cost of gas
= 384 × 11p = 4224 p
100 p ≡ £ 1
Therefore 4224 p = £42.24 p
The total cost of the gs is obtained by adding the fixed charge to the cost of gas consmed as follows
£25.57 + £42.24 = £67.81 p
The cost of the gas = £67.81 p
Answer:
The Answer is B) Hope it helps!
Step-by-step explanation:
Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
