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Umnica [9.8K]
1 year ago
14

When two events are​ independent, the probability of them both occurring is simply the product of their individual probabilities

of occurring?
Mathematics
1 answer:
Sholpan [36]1 year ago
5 0
Yes this is correct.

If event A and event B are independent, then 
P(A and B) = P(A)*P(B)

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Solve the equation using square roots. 6x2 = 54
Mars2501 [29]
6x^2 = 54

6(x^2) = 54

6(x^2)/6 = 54/6

x^2 = 9

rt(x^2) = rt(9)

x = 3

hope this helps
5 0
1 year ago
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An investigation of a number of automobile accidents revealed the following information:
seropon [69]

Answer:

59 accidents were investigated.

Step-by-step explanation:

The question above is a probability question that involves 2 elements: causes of accidents.

Let

A = Alcohol

E = Excessive speed

In the question, we are given the following information:

18 accidents involved Alcohol and Excessive speed =P(A ∩ E)

26 involved Alcohol = P(A)

12 accidents involved excessive speed but not alcohol = P( E ) Only

21 accidents involved neither alcohol nor excessive speed = neither A U B

We were given P(A) in the question. P(A Only) = P(A) - P(A ∩ E)

P(A Only) = 26 - 18

= 8

So, only 8 accident involved Alcohol but not excessive speed.

The Total number of Accidents investigated = P(A Only) + P( E only) + P(A ∩ E) + P( neither A U B)

= 8 + 12 + 18 + 21

= 59

Therefore, 59 accidents were investigated.

3 0
2 years ago
Semielliptical Arch Bridge An arch for a bridge over a highway is in the form of half an ellipse. The top of the arch is 20 feet
photoshop1234 [79]

Answer:

the span of the bridge is 73.7 feet

Step-by-step explanation:

The equation of an ellipse with a vertical major axis(i.e major axis parallel to y axis) is given by:

\frac{(x-h)^{2} }{b^{2} } + \frac{(y-k)^{2} }{a^{2} }= 1 a>b

where (h,k) are the coordinates of the center of the ellipse, a is the length of the major axis and b is the length of the minor axis

For this problem, the center of the ellipse (h,k) = (0,0)

Therefore:

\frac{(x)^{2} }{b^{2} } + \frac{(y)^{2} }{a^{2} }= 1

The top of the arch is 20 feet above the ground level (the major axis), therefore a=20

length of the major axis = 2a= 2*20 = 40

\frac{x^{2} }{b^{2} } + \frac{y^{2} }{20^{2} }= 1\\\frac{x^{2} }{b^{2} } + \frac{y^{2} }{400 }= 1

The coordinates of the ellipse (x,y) = (28,13)

\frac{28^{2} }{b^{2} } + \frac{13^{2} }{400 }= 1

\frac{28^{2} }{b^{2} } + 0.4225= 1

\frac{784 }{b^{2} } = 0.5775

b² ≅ 1358

b≅36.85

Length of minor axis (2b) = 73.7 feet.

the span of the bridge is 73.7 feet

7 0
2 years ago
An employee worked 8 hours on 2 days, 6 hours on 1 day, and 4 hours on 2 days. What is the average number of hours the employee
Gnesinka [82]
Average of 6 hours per day
5 0
2 years ago
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A scale drawing of a rectangular park is 5 inches wide and 7inches long. The actual park is 280 yards long. What is the area of
choli [55]

280÷7=40. 280-80 = 200. 200×280=5,600 Length divided by scale length to find the amount that each inch scale size equals 40 yards per inch. 5 inches equals 200 yards Then multiply length times width. 200x280=5,600 yds  

7 0
1 year ago
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