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QveST [7]
1 year ago
10

Consider the discussion in our Devore reading in this unit involving an important distinction between mean and median that uses

the concept of a trimmed mean to highlight an important continuum between the two. Presuming that the mean and median are different values for a distribution, the mean can be taken to indicate a 0% trim, and the median can be taken to approach a 50% trim (with effectively 100% of the values removed). These two values define a continuum of trimmed mean values that would fall between the two. Discuss why the mean and median of the distribution always approach each other as we take trimmed means at higher and higher percentages (e.g., 10%, 20%, 30% ...). In particular, describe what is happening to the kurtosis and skewness of the distribution as we trim off more and more data. Speculate on whether or not you might expect to see an optimum point in that process at some value between the mean and median. (Hint: You should!) Why might this matter?
Mathematics
1 answer:
Levart [38]1 year ago
3 0

Answer:

Step-by-step explanation:

A trimmed mean is a method of averaging that removes a small designated percentage of the largest and smallest values before calculating the mean. After removing the specified observations, the trimmed mean is found using a standard arithmetic averaging formula. The use of a trimmed mean helps eliminate the influence of data points on the tails that may unfairly affect the traditional mean.

trimmed means provide a better estimation of the location of the bulk of the observations than the mean when sampling from asymmetric distributions;

the standard error of the trimmed mean is less affected by outliers and asymmetry than the mean, so that tests using trimmed means can have more power than tests using the mean.

if we use a trimmed mean in an inferential test , we make inferences about the population trimmed mean, not the population mean. The same is true for the median or any other measure of central tendency.

I can imagine saying the skewness is such-and-such, but that's mostly a side-effect of a few outliers, the fact that the 5% trimmed skewness is such-and-such.

I don't think that trimmed skewness or kurtosis is very much used in practice, partly because

If the skewness and kurtosis are highly dependent on outliers, they are not necessarily useful measures, and trimming arbitrarily solves that problem by ignoring it.

Problems with inconvenient distribution shapes are often best solved by working on a transformed scale.

There can be better ways of measuring or more generally assessing skewness and kurtosis, such as the method above or L-moments. As a skewness measure (mean ? median) / SD is easy to think about yet often neglected; it can be very useful, not least because it is bounded within [?1,1][?1,1].

i expect to see the optimum point in that process at some value between the mean and median.

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James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28.
lara31 [8.8K]
Let's use J for James's age and A for Austin's age. The equations are:

J = A - 4
3J + A² = 28

Just plug (A - 4) in the place of J in the second equation. This gives you:

3(A - 4) + A² = 28
-->
A² + 3A - 12 = 28
--> 
A² + 3A - 40 = 0
--> 
(A - 5)(A + 8) = 0
-->
A = 5 or -8

-8 is nonsense, so Austin is 5 years old. Therefore, James is 1 year old.
7 0
1 year ago
15x²y³z÷3xy² simplify
umka21 [38]

Answer:

5xyz

Step-by-step explanation:

\frac{15x^2y^3z}{3xy^2}

Step 1: Divide the numbers

\frac{15}{3}=5\\\\=\frac{5x^2y^3z}{xy^2}

Step 2: Simplify

\frac{x^2}{x}\\\\= x\\\\=\frac{5xy^3z}{y^2}

Step 3: Simplify

\frac{y^3}{y^2} = y\\\\=5xyz

Therefore, the simplified answer is =5xyz

7 0
1 year ago
Read 2 more answers
A map of Colorado says that the scale is 1 inch to 20 miles or 1 to 1,267,200. Are these two ways of reporting the scale the sam
goldenfox [79]

Answer:

1,267,200

Step-by-step explanation:

Given that the map reported that the scale is 1 inch to 20 miles.

Recall that there are 63,360 inches in 1 mile, thus, in 20 miles, we have 20 x 63,360 = 1,267,200

Therefore, the scale of 1 inch to 20 miles can also be represented as 1 to 1,267,200

4 0
1 year ago
An upscale resort has built its circular swimming pool around a central area that contains a restaurant. The central area is a r
Elena L [17]
The problem is modelled in the diagram below 

Question 1:
The largest area of the pool is half of the area of the circle

Area of circle = πr², where r is the radius given by 1/2 of the diameter
Area of circle = π(60)² = 11309.73355 feet

Area of half of the circle is 11309.73355/2 = 5654.866... ≈ 5654.87 feet (2dp)

Question b:

The area of the pool is the area of the circle subtracts the area of the triangle.

The area of the circle is 11309.73²

The area of the triangle is 1/2 (60×103.92) = 3117.6 feet²

The area of the pool is 11309.73 - 3117.6 = 7922.13 feet²

The volume of the pool = 7922.13 × 4 = 31688.52 feet³

Note: there isn't any information on the fish tank part so the answer above is assumed for the whole pool.

6 0
1 year ago
The table shows the number of condo sales per month for a new condo building.
Tresset [83]

Answer:

Do you happen to have the graph or anything to add to it? Because it is kind of difficult to see when it looks like that. I think it would be 11, 8, 5, and

y-2--3(x-3)

y+ 11 = 31-0)

y+ 1 =-3(x-2)

Y-1--31% +8)

y-11 =-3lx -0)

8 0
2 years ago
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