answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
QveST [7]
2 years ago
10

Consider the discussion in our Devore reading in this unit involving an important distinction between mean and median that uses

the concept of a trimmed mean to highlight an important continuum between the two. Presuming that the mean and median are different values for a distribution, the mean can be taken to indicate a 0% trim, and the median can be taken to approach a 50% trim (with effectively 100% of the values removed). These two values define a continuum of trimmed mean values that would fall between the two. Discuss why the mean and median of the distribution always approach each other as we take trimmed means at higher and higher percentages (e.g., 10%, 20%, 30% ...). In particular, describe what is happening to the kurtosis and skewness of the distribution as we trim off more and more data. Speculate on whether or not you might expect to see an optimum point in that process at some value between the mean and median. (Hint: You should!) Why might this matter?
Mathematics
1 answer:
Levart [38]2 years ago
3 0

Answer:

Step-by-step explanation:

A trimmed mean is a method of averaging that removes a small designated percentage of the largest and smallest values before calculating the mean. After removing the specified observations, the trimmed mean is found using a standard arithmetic averaging formula. The use of a trimmed mean helps eliminate the influence of data points on the tails that may unfairly affect the traditional mean.

trimmed means provide a better estimation of the location of the bulk of the observations than the mean when sampling from asymmetric distributions;

the standard error of the trimmed mean is less affected by outliers and asymmetry than the mean, so that tests using trimmed means can have more power than tests using the mean.

if we use a trimmed mean in an inferential test , we make inferences about the population trimmed mean, not the population mean. The same is true for the median or any other measure of central tendency.

I can imagine saying the skewness is such-and-such, but that's mostly a side-effect of a few outliers, the fact that the 5% trimmed skewness is such-and-such.

I don't think that trimmed skewness or kurtosis is very much used in practice, partly because

If the skewness and kurtosis are highly dependent on outliers, they are not necessarily useful measures, and trimming arbitrarily solves that problem by ignoring it.

Problems with inconvenient distribution shapes are often best solved by working on a transformed scale.

There can be better ways of measuring or more generally assessing skewness and kurtosis, such as the method above or L-moments. As a skewness measure (mean ? median) / SD is easy to think about yet often neglected; it can be very useful, not least because it is bounded within [?1,1][?1,1].

i expect to see the optimum point in that process at some value between the mean and median.

You might be interested in
A square with side length c has an area of 81 square centimeters. The following equation shows the area of the square. c^2 = 81.
kramer

Answer:

9 cm

Step-by-step explanation:

c^2=81

Take the square root of both sides.

The square root of c^2 is c.

The square root of 81 is 9.

c=9

8 0
2 years ago
Read 2 more answers
Which graph represents y=3 sqrt x+2
ziro4ka [17]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=3\sqrt{x+2}

Remember that the radicand must be greater than or equal to zero

so

x+2\geq 0

solve for x

subtract 2 both sides

x\geq -2

The domain is the interval [-2,∞)

All real number greater than or equal to -2

For x=-2

y=3\sqrt{-2+2}=0

so

The range is the interval [0,∞)

All real number greater than or equal to 0

Find the y-intercept

Remember that the y-intercept is the value of y when the value of x is equal to zero

For x=0

y=3\sqrt{0+2}

y=3\sqrt{2}

y=4.243

The y-intercept is the point (0,4.243)

therefore

The graph in the attached figure

7 0
2 years ago
Paula and Kawai shared $312 in the ratio of 6:7. How much money<br> did each person get?
Maslowich

Answer:

Paula get \$144 and Kawai get \$168.

Step-by-step explanation:

Given: Paula and Kawai shared \$312 in the ratio of 6:7.

To find: How much money  did each person get?

Solution:

We have,

Paula and Kawai shared \$312 in the ratio of 6:7.

So, let Paula get \$6x and Kawai get \$7x.

As per the question,

6x+7x=312

\implies13x=312

\implies x=\frac{312}{13} =24

Therefore, Paula get 6\times 24=\$144, and Kawai get 7\times 24=\$168.

Hence, Paula get \$144 and Kawai get \$168.

6 0
2 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have DE=7\ units

DG=AG-AD=9-7=2\ units

substituteA=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
2 years ago
Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re
attashe74 [19]

Answer: \frac{11}{15}

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

LCM=5*3=15

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}

7 0
2 years ago
Other questions:
  • What are the possible values of x if (4x – 5)2 = 49? check all that apply. -4/5 -1/2 3 5 7
    8·2 answers
  • In the diagram, polygon ABCD is flipped over a line of reflection to make a polygon with vertices at A′, B′, C′, and D′. Points
    13·1 answer
  • Adam is building a rectangular swimming pool. The perimeter of the pool must be no more than 120 feet. If the length of the pool
    13·1 answer
  • Firewood is stacked in a pile. The bottom row has 20 logs, and the top row was 14 logs. Each row has one more log than the row a
    5·2 answers
  • Describe the steps you used to solve the equation and find the amount of Carrie’s allowance. Linear equation:  1 4 a + 1 3 a + 8
    6·2 answers
  • Country A produces about four times the amount of diamonds in carats produced in country B. If the total produced in both countr
    6·1 answer
  • Jane buys \dfrac73 \text { yard} 3 7 ​ yardstart fraction, 7, divided by, 3, end fraction, start text, space, y, a, r, d, end te
    15·1 answer
  • A scientist is filling beakers of water for an experiment. He begins with 3 liters of water in a large container and each beaker
    14·1 answer
  • a researcher is testing reaction times between the dominant and non-dominant hand. they randomly start with each hand for 20 sub
    10·1 answer
  • Researchers studied the mean egg length​ (in millimeters) for a particular bird population. After a random sample of​ eggs, they
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!