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Fiesta28 [93]
1 year ago
14

Yuto left his house at 10 a.m. to go for a bike ride. By the time Yuto’s sister Riko left their house, Yuto was already 5.25 mil

es along the path they both took. If Yuto’s average speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, over what time period in minutes, t, starting from when Riko left the house, will Riko be behind her brother?
Mathematics
2 answers:
Nadusha1986 [10]1 year ago
7 0

Answer:

The solution means that Riko will be behind Yuto from the time she leaves the house, which corresponds to t = 0, until the time she catches up to Yuko after 52.5 minutes, which corresponds to t = 52.5. The reason that t cannot be less than zero is because it represents time, and time cannot be negative.

Hope this helps!!! :) Have a great day/night.

Akimi4 [234]1 year ago
4 0

Answer:

52 minutes and 30 seconds

Step-by-step explanation:

You know that Yuto has ridden for 5.25 miles when Riko left their house and you need to know and what time they will be together:

Then you can say that:

5.25 miles+(yutos speed)*t= (Rikos speed)*t

when t=Time in minutes when they will be together

5.25 miles+(0.25miles/min)*t= (0,35miles/min)*t

5.25miles=(0.35miles/min-0.25miles/min)*t

5.25miles/(0.35miles/min-0.25miles/min)=t

t=52.5 min =52 minutes and 30 seconds

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What is the value of y in the following system y= 3x-5 6x+3y=15
Misha Larkins [42]
X=2. You use substitution to put the y=3x-5 into 6x+3y=15.
So you get 6x+3(3x-5)=15
=6x+9x-15=15
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6+9=15 -- 15+15=30
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7 0
2 years ago
Read 2 more answers
Bags of sugar from a production line have a mean weight of 5.020 kg with a standard deviation of 0.078 kg. The bags of sugar are
Sindrei [870]

Answer:

a.0.126

b.100.6356

c.5.010

Step-by-step explanation:

4 0
1 year ago
SAT Writing scores are normally distributed with a mean of 491 and a standard deviation of 113.A university plans to send letter
Sholpan [36]

Answer:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(491,113)  

Where \mu=491 and \sigma=113

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.08   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.92 of the area on the left and 0.08 of the area on the right it's z=1.405. On this case P(Z<1.405)=0.92 and P(z>0.92)=0.08

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

6 0
1 year ago
A local cable company claims that the proportion of people who have Internet access is less than 63%. To test this claim, a rand
MaRussiya [10]

Answer:

Step-by-step explanation:

For the null hypothesis,

H0 : p = 0.63

For the alternative hypothesis,

Ha : p < 0.63

This is a left tailed test

Considering the population proportion, probability of success, p = 0.63

q = probability of failure = 1 - p

q = 1 - 0.63 = 0.37

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 478

n = number of samples = 800

P = 478/800 = 0.6

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76

From the normal distribution table, the area below the test z score in the left tail 0.039

Thus

p = 0.039

7 0
1 year ago
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