David has twice as many cousins as Becky.
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Bernard’s walking speed is 140 meters per minute
Bernard’s walking speed is 8.4 kilometers per hour
Step-by-step explanation:
The pace length P is the distance between the rear of two consecutive footprints
The formula, n P = 140, gives an approximate relationship between n and P where,
- n = number of steps per minute
- P = pace length in meters
- Bernard knows his pace length is 0.80 meters
- The formula applies to Bernard’s walking
We need to calculate Bernard’s walking speed in meters per minute and in kilometers per hour
∵ n = number of steps per minute
∴ n unit is number / minute
∵ P = pace length in meters
∴ P unit is meter
- That means n P unit is meters/minute
∴ n P represents the speed in meters per second
∵ The formula applies to Bernard’s walking
∵ His pace length is 0.80 meters
∵ n P = 140
∴ n(0.8) = 140
- Divide both sides by 0.8
∴ n = 175
- That means he moves 175 steps per minute
∵ The distance he walks in minute = 175 × 0.8 = 140 meters/minute
∴ His speed is 140 meters per minute
Bernard’s walking speed is 140 meters per minute
∵ 1 km = 1000 m
∵ 1 hour = 60 minutes
- Divide the meters by 1000 and the minute by 60 to change
from meters per minute to kilometers per hour
∴ His walking speed = ÷
- Change ÷ to × and reciprocal the fraction after the division sign
∴ His walking speed = ×
= 8.4 km/h
Bernard’s walking speed is 8.4 kilometers per hour
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Answer:
We conclude that a web-based company are not exceeding their goal of 90%.
Step-by-step explanation:
We are given that a web-based company has a goal of processing 90 percent of its orders on the same day they are received.
434 out of the next 471 orders are processed on the same day.
Let p = <u><em>proportion of orders processing on the same day they are received.</em></u>
SO, Null Hypothesis, : p
0.90 {means that they are not exceeding their goal of 90%}
Alternate Hypothesis, : p > 0.90 {means that they are exceeding their goal of 90%}
The test statistics that would be used here <u>One-sample z test for</u> <u>proportions</u>;
T.S. = ~ N(0,1)
where, = sample proportion of orders that are processed on the same day =
= 0.92
n = sample of orders = 471
So, <u><em>the test statistics</em></u> =
= 1.599
The value of z test statistics is 1.599.
<u>Now, at 0.025 significance level the z table gives critical value of 1.96 for right-tailed test.</u>
Since our test statistic is less than the critical value of z as 1.599 < 1.96, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.
Therefore, we conclude that a web-based company are not exceeding their goal of 90%.