1+3+7=11
The first part is
3,300×(1÷11)
=300
The second part is
3,300×(3÷11)
=900
the third part is
3,300×(7÷11)
=2,100
First, we solve for the number of minutes in 7 and 3/5 hours by multiplying the number by 60 giving us,
(7 + 3/5) x (60) = 456 minutes
Spending 30 minutes for lunch will leave her with 426 minutes. Then, spending 42 minutes for switching of classes will finally give her 414 minutes.
We then divide this value by 6 (for her 6 classes) giving us 69 minutes. Thus, each class is 69 minutes long.
Based on the scenario, the case must be filled like this :
blue/green/black x blue/ green/black x blue/green/black x random x random
Different ways he can arrange it :
3 x 5!/(2!x2!) + 3x <span>5!/3!
</span>
90 + 60
= 150 ways
hope this helps
For this case we have the following inequality: y < 3x + 1 < br/ >
What we must do is to evaluate a point of the Cartesian plane and verify if it is in the shaded region.
The shaded region represents the solution of the system of equations.
For the point (0, 0) we have:
0 < 3(0) + 1 < br / >
0 < 0 + 1 < br / >
0 < 1 < br / >
Therefore, the point (0, 0) is in the shaded region because it satisfies the inequality.
Then, the points that are on the line, are not part of the solution because the sign is of less strict.
Hope I helped ~~Laurel
Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
•x=(15x+90)/2
•2x=15x+90
•-13x=90
X= -90/13
Now. Y= 3x/2=-270/26
Therefore total
no. Of students= -270/26+(-90/13)
•no. Of students= -450/26
According to me this is an imaginary question i mean how can their be a negative person
