Answer:
<u>Marge's</u> present age = 14 ; <u>Dan's</u> present age = 29
Step-by-step explanation:
Let Marge's present age be = M
Dan's present age [D] : 14 years elder than Marge = M + 14
Marge Age = M - 8
Dan's Age = D - 8 = (M + 14) - 8 = M + 6
{Given} : Dan's age = 3 times Marge's age
M + 6 = 3 (M - 8)
M + 6 = 3M - 24
6 + 24 = 3M - M
30 = 2M
M = 30/2
M = 15 [Marge's present age]
Dan's present age [D] = M + 14 = 29
Answer:
G = 14 - 1.75(t)
Where G is the number of gallons of gas remaining;
14 represents the amount of gas in gallons in the full gas tank of the vehicle
t is the number of hours
Step-by-step explanation:
Here, we want to write an equation.
We are told that the car uses 1.75 gallons of gas every hour and after 4 hours 7 gallons were left
In the 4 hours, the amount of fuel used will be 1.75 * 4 = 7 gallons
So therefore since we have 7 gallons left, the amount of gallons in the full tank of the vehicle will be 7 + 7 = 14 gallons
Hence, the equation we want to write will be;
G = 14 - 1.75(t)
Answer:
$24.09
Step-by-step explanation:
you do 984.20-381.80=602.4
then divide 602.4 by 1/4
which 1/4=25.
then you get $24.09
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
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