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larisa86 [58]
2 years ago
10

7700 dollars is placed in an account with an annual interest rate of 5.75%. How much will be in the account after 24 years, to t

he nearest cent?
Mathematics
1 answer:
Amanda [17]2 years ago
4 0

Answer:

A = $18,326.00

(assuming simple interest)

Step-by-step explanation:

Assuming simple interest, the following formula applies:

final amount = (principal amount) x [1  + (annual rate)(time elapsed) ]

or

A = P (1 + rt)

in our case,

P = $7,700

r = 5.75% = 0.0575

t = 24 years

hence,

A = 7700 [ 1 + (0.0575)(24)]

A = 7700 ( 1 + 1.38)

A = 7700 x 2.38

A = $18,326.00  

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108.80

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Why did the paper rip when the student tried to stretch out the horizontal axis of his graph? Unscramble this letters to figure
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2 years ago
A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
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Nitella [24]

In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).              

 

To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.

<u>The equation for the hole</u>

x^{2} + y^{2} = 5   (1)

<u>The equation for the path of the bean bag</u>

y = 0.5x^{2} + 1.5x - 4    (2)

By entering equation (2) into (1) we have:  

x^{2} + (0.5x^{2} + 1.5x - 4)^{2} = 5

x^{2} + 0.25x^{4} + 1.5x^{3} - 4x^{2} + 2.25x^{2} - 12x + 16 = 5    

0.25x^{4} + 1.5x^{3} - 0.75x^{2} - 12x + 11 = 0

By solving for <em>x</em>, we have:

x₁ = 1

x₂ = 2

Now, for <em>y</em> we have (eq 2):

  • <u>x₁ = 1</u>    

y_{1} = 0.5(1)^{2} + 1.5(1) - 4 = -2

  • <u>x₂ = 2</u>

y_{2} = 0.5(2)^{2} + 1.5(2) - 4 = 1                                              

Therefore, the points are (1, -2) or (2, 1).

To find more about intersections, go here: brainly.com/question/4977725?referrer=searchResults        

I hope it helps you!

8 0
2 years ago
What is the volume of a cylinder with base radius 222 and height 666? either enter an exact answer in terms of \piπpi or use 3.1
Leno4ka [110]

In this question, it is given that the base radius is 2 , height is 6 and the value of pi is 3.14 .

And we have to find the volume of the cylinder, and for that, we have to use the following formula

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Substituting the values of pi,r and h, we will get

V = 3.14(2)^2 * 6 = 75.36 \ cubic \ units

3 0
2 years ago
Read 2 more answers
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