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allsm [11]
2 years ago
13

1. Find an odd natural number x such that LCM (x, 40)= 1400

Mathematics
1 answer:
aleksklad [387]2 years ago
4 0

The odd natural number which is mentioned as X is 175.

<u>Step-by-step explanation:</u>

  • By prime Factorization method .
  • Step 1  : The prime factor for 40 is = 2×2×2×5.
  • Step 2 :The prime factor for 1400 is = 2×2×2×5×5×7.
  • Step 3 : the prime factor for the unknown  natural odd number is to be find by comparing the factors of 40 and 1400.
  • Step 4 : Lcm is known as least common multiple.
  • Step 5 : Thus we can see  the 5×5×7 in 1400 as different factors from the factors of 40.
  • Step 6 : So lets multiply the factors we get number 175 which satisfies the condition of the odd number.
  • Step 7 :  The prime factors of 175 are 5×5×7.

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Sarah buys 2 candy bars for $1.45. how much would one candy bar cost
sattari [20]
2 = $1.45
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2 years ago
The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $
IRISSAK [1]
<h3>Answer:</h3>

equations

  • 20a +10c = 15000
  • c = 3a

solution

  • 300 adult
  • 900 children's
<h3>Step-by-step explanation:</h3>

Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:

... 20a +10c = 15000 . . . . . . total revenue from ticket sales

... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold

Using the expression for c, we can substitute into the first equation to get ...

... 20a +10(3a) = 15000

... 50a = 15000

... a = 15000/50 = 300 . . . . . adult tickets sold

... c = 3·300 = 900 . . . . . children's tickets sold

8 0
2 years ago
Find a weight in kilograms of 150 pound person round to the nearest hundred
3241004551 [841]

Answer:

68.04

Step-by-step explanation:

3 0
2 years ago
charles deposited $12,000 in the bank. He withdrew $5,000 from his account after one year. If he recives a total amount of $9,34
Schach [20]

Answer:

The rate of simple interest is 9%

Step-by-step explanation:

* Lets talk about the simple interest

- The simple Interest Equation (Principal + Interest)  is:

  A = P(1 + rt)  , Where

# A = Total amount (principal + interest)

# P = Principal amount

# I = Interest amount

# r = Rate of Interest per year in decimal r = R/100

# R = Rate of Interest per year as a percent R = r * 100

# t = Time period involved in months or years

- The rule of the simple interest is I = Prt

* lets solve the problem

- Charles deposited $12,000

∴ P = $12,000

- He withdrew $5,000 from his account after one year

- He receives a total amount of $9,340 after 3 years

∴ A = $9340 and t = 3

- Lets find the inetrest after 1 year

∵ I = Prt

∵ P = 12000

∵ t = 1

∴ I = 12000(r)(1) = 12000r

- Lets subtract the money that he withdrew

∵ He withdrew $5000

∵ He deposit at first 12000

∴ He has after the withdrew 12000 - 5000 = 7000

- The new P for the next 2 years is 7000

- This amount will take the same rate r for another two years

- The total money is $9340

∵ I = A - P

∵ A = 9340

∵ P = 7000

∴ The amount of interest = 9340 - 7000 = 2340

- The amount of interest after 3 years is 2340

- Lets find the amount of interest in the two years

∴ I = 7000(r × 2) = 14000r

- The amount of interest after the 3 years is the sum of the interest in

  the 1st year and the other 2 years

∴ 2340 = 14000r + 12000r

∴ 2340 = 26000r ⇒ divide both sides bu 2340

∴ r = 2340 ÷ 26000 = 0.09

∵ The rate R in percentage = r × 100

∴ R = 0.09 × 100 = 9%

∴ The rate of simple interest is 9%

8 0
2 years ago
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katrin2010 [14]

Answer:

-1.14

Step-by-step explanation:

The given information in statement is

mean=μ=69

standard deviation=σ=3.5

Let X be the Ishaan's exam score

X=65

The Z score can be computed as

z=\frac{x-mean}{standard deviation}

z=\frac{65-69}{3.5}

z=-1.1429

z=-1.14 (rounded to two decimal places).

Thus, the computed z-score for Ishaan's exam grade is -1.14.

4 0
2 years ago
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