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Anit [1.1K]
2 years ago
11

An art club sells 42 large candles and 56 small candle price of large candle is $10 the cost is $x a small candles cost $5 and c

ost is $y use the distributive property to right and simplify an expression for the profit
Mathematics
1 answer:
balandron [24]2 years ago
4 0

Answer:

Profit = $(700 - 42x - 56y)

Step-by-step explanation:

For large candles, the selling price is $10 and its making cost is $x.

So, by selling a large candle the profit is $(10 - x)

Again for small candles, the selling price is $5 and its making cost is $y.

So, by selling a small candle the profit is $(5 - y)

Therefore, in a sell of 42 large candles and 56 small candles the total profit will be, P = 42 (10 - x) + 56 (5 - y)

⇒ P = 420 - 42x + 280 - 56y {Applying distributive property}

⇒ P = $(700 - 42x - 56y) (Answer)

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Read the ruler in millimeters to the correct degree of precision (The ruler is in between the halfmark and the sixth mark on the
Vitek1552 [10]

Answer:

3 1/2

Step-by-step explanation:

6 0
2 years ago
Given the values of the linear functions f (x) and g(x) in the tables, where is (f – g)(x) positive?
alexandr402 [8]

Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9) .

----------------------

  • For the subtraction function, we simply subtract both functions, thus:

(f - g)(x) = f(x) - g(x)

  • It is positive if f is greater than g, that is: f(x) > g(x).
  • It is a linear function, so one function is greater before the equality, one after.
  • They are equal at x = 9.
  • If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:

(–∞, 9)

A similar problem is given at brainly.com/question/24610273

4 0
1 year ago
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
2 years ago
Statements about regression
galben [10]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

  • It is true because the square of the standard error of its estimate was its total square error divided only by the degree of freedom.  
  • It is true because Its coefficient with Standardized Regression, beta, will have the same value as r, the approximate similarity.  
  • It is false because Its slope b, of its equation of regression, will have the same value as r, the projected correlation.
3 0
2 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Bumek [7]

Answer:

x+178x=2000 cans

Step-by-step explanation:

Hope this Helped

3 0
2 years ago
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