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1 year ago

What is the difference between a slope change and a translation

Mathematics

1 answer:

romanna [79]1 year ago

7 0

Answer:

Translation describes movement of an object without change of size where as the change in slope describes the variation in steepness of an object. Step-by-step explanation: ... Slope is the ratio of vertical and horizontal changes between two points on a surface or line.

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Sole the equation 6n + 9 = -3n - 21 - 6 for n

lesya692 [45]

N is -4
$6n + 9 = - 3n - 21 - 6 \\ 9n = - 36 \\ n = \frac{ - 36}{9} = - 4$

good luck

4 0

2 years ago

Read 2 more answers

JL has coordinates J(-6, 1) and L(-4,3).<br> Find the coordinates of the midpoint.

ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴ $x_{1}$ = -6 and $y_{1}$ = 1

∵ The coordinates of L are (-4 , 3)

∴ $x_{2}$ = -4 and $y_{2}$ = 3

Lets use the rule above to find the mid-point of JL

∵ $x=\frac{-6+-4}{2}=\frac{-10}{2}$

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵ $y=\frac{1+3}{2}=\frac{4}{2}$

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

5 0

2 years ago

Find the length of the leg of a right triangle with leg length b= 21.5 inches and the hypotenuse c= 31.9 inches. Use a calculato

sweet [91]

Answer:

23.6 (approximate value)

Step-by-step explanation:

a*a+b*b=c*c Pythagorean thereom
(21.5)^2 + b*b = (31.9)^2
b*b= 1017.61 - 462.25
√b*b= √555.36
b=23.6(approximate value)

8 0

2 years ago

John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S

Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work $=20\ km/hr$

Sheri's commute to work $=500\ m/min$

$1.61\ km = 1\ mile$

John's commute to work in miles per hour = $\frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr$

Sheri's commute to work in miles per hour = $\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr$

We can see that Sheri has a faster commute.

Difference between the rates = $18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr$

∴ Sheri has the faster commute by 6.2 miles/hr.

3 0

2 years ago

Imagine your friend is writing an argument to convince adults that they should allow teens to own and use smartphones. Read her

Blababa [14]

I think it is the 2nd one

5 0

2 years ago