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1 year ago

Round 4,398,202 to the nearest 100

2 answers:

8 0

First off, let's take a look at the digit that's in the hundred's place.
--
4,398,202
^
2 is in the hundred's place
--
Now, let's take a look at the digit on the right of 2.
--
4,398,202
^
0 is on the right of 2.
--
Any number between 0-4:
You leave the place value alone and change every other digit to the right of the place value to 0.

5-9: Same rule, only add one to the place value.
--
Since 0 is to the right, we change every number to the right of 2 to 0. The answer is:

4,398,200

:D

Klio2033 [76]1 year ago

5 0

In the hundreds spot is a 2 and 2 is under 5 so we round down which would be 4 398 200

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A reflection followed by a translation

Step-by-step explanation:

A reflection across they x-axis would put all the points in the right section and on the right y value. The x value would need to be changed though. So, you would need to do a translation of 4 on all points.

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2 years ago

Charlie bought a pair of shorts at the store when they were having a 45% off sale. If the regular price of the pair of shorts wa

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2 years ago

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During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

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Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

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1 year ago

What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768

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Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

Decimal form = 0.8

Fraction form = 4/5

Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

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2 years ago

Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose the outcomes are equally likely. Compute the probability of

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Answer:

The probability is 3/5

Step-by-step explanation:

Given,

Sample space, S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10},

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So, the probability of the event E,

$P(E) =\frac{n(E)}{n(S)}$

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$=\frac{3}{5}$

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1 year ago