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2 years ago

14

A bearing, measured at 1.234 inches with a caliper, must be replaced. Since the bearings are sized in 64ths of an inch, find the

closest fractional size.

1 answer:

Ganezh [65]2 years ago

7 0

We have
1.234 in-----> 1+(0.234) in

we know that
1/64=0.015625
so
0.234/0.015625=14.98-----> 15
15/64-----> 0.234

therefore
1.234 in is equal to -----------> 1 15/64 in

the answer is
1 15/64 in

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Step-by-step explanation:

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The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Confidence =95% or 0.995

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$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are df=n-1=48-1=47

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Now we have everything in order to replace into formula (1):

$530-2.01\frac{70}{\sqrt{48}}=509.692$

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The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Assuming that $\hat \sigma =s$

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So the answer for this case would be n=523 rounded up to the nearest integer

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