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GenaCL600 [577]
1 year ago
12

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

o see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n = 15, t = 1.66, a = 0.05
a. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
b. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
c. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
d. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n = 15, t = 1.66, a = 0.05
a. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
b. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
c. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
d. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n = 26, t = 2.55, a = 0.01
a. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
b. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
c. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
d. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n = 26, t = 3.95
a. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
b. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
c. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
d. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
You may need to use the appropriate table in the Appendix of Tables to answer this question.

Mathematics
1 answer:
Naily [24]1 year ago
8 0

Answer:

Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in

Step-by-step explanation:

We are given;

n = 15

t-value = 1.66

Significance level;α = 0.05

So, DF = n - 1 = 15 - 1 = 14

From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14

Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.

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Write two numbers that when rounded to the greatest place value have an estimated sum of 11,000 and an estimated difference of 3
lianna [129]

Answer:

x + y = 10,999.5 (rounded up to 11000)

x - y =  3,000.3 (this would be rounded down to 3000)

Step-by-step explanation:

Assume;

Two numbers are x, y

So,

x + y = 11,000 .......eq1

x - y = 3,000 .........eq2

eq1 + eq2

So,

2x =14,000

x = 7,000

So y = 4,000

For rounding number

x = 6,999.9 (rounded up to 7,000)

y = 3,999.6 (rounded up to 4,000)

Sum;

x + y = 10999.5 (rounded up to 11000)

x - y =  3000.3 (this would be rounded down to 3000)

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2 years ago
Alice and Betsy agreed to meet at 3:00PM and o shopping in one of the 6 clothing stores in their hometown.. However, they forgot
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2 years ago
1. Lisa and Tomas Lopez are buying a new minivan that has a base
Dimas [21]

The question is incomplete:

Lisa and Tomas Lopez are buying a new minivan that has a base price of $22,510.the options total $8,062 and destination charge is $770. The dealer's cost is estimated to be 91% of the base price and 88% of the options.

-What is the sticker price of the vehicle?

-Find the dealer's percent of the base price.

-Find the dealer's percent of the options price.

-What is the estimated dealer's cost?

Answer:

-What is the sticker price of the vehicle? $31,342

-Find the dealer's percent of the base price: $20,484

-Find the dealer's percent of the options price: $7,094

-What is the estimated dealer's cost?  $28,348

Step-by-step explanation:

-The sticker price is the result of adding the base price plus the options plus the destination charge.

Sticker price= base price + options + destination charge

Sticker price= $22,510+$8,062+$770

Sticker price= $31,342

-Dealer's percent of the base price: It is  91% of the base price:

$22,510*91%= $20,484

-Dealer's percent of the options price: It is  88% of the options:

$8,062*88%= $7,094

-Estimated dealer's cost= Percent of base price+percent of options price+destination charge

Estimated dealer's cost= $20,484+$7,094+$770

Estimated dealer's cost=$28,348

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2 years ago
Consider the trinomial 9x2 + 21x + 10. What value is placed on top of the X? What value is placed on the bottom of the X? What i
inna [77]

Answer: 1) Value is placed on top of the X =90

2) Value is placed on the bottom of the X =21

3)  Factored form will be (3x+5)(3x+2)

Step-by-step explanation:

Since we have given that

9x^2 + 21x + 10

As we know the quadratic form :

ax^2+bx+c=0

1) Value is placed on top of the X is given by

a\times c=9\times 10=90

2) Value is placed on the bottom of the X is given by

b=21

3) Factorised form:

We will use "Split the middle term":

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Hence, Factored form will be

(3x+5)(3x+2)

7 0
2 years ago
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