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2 years ago

Mr. Jones asks his students to generate the next two numbers in the sequence beginning –5.5, 11, ....

Mathematics

2 answers:

pishuonlain [190]2 years ago

9 0

Answer:

the answer is D

Step-by-step explanation:

Alexandra [31]2 years ago

5 0

Answer:

Option D Both students could be correct. Because the numbers are given in the original sequence, it is possible to find a common difference and common ratio between the successive terms.

Step-by-step explanation:

A geometric sequence has a common ratio. Here, that ratio would be 11/-5.5 = -2 if the sequence is geometric. That ratio would mean the next two terms are ...

11 × -2 = -22

-22 × -2 = 44

An arithmetic sequence has a common difference. Here, that difference would be 11 -(-5.5) = 16.5 if the sequence is arithmetic. That difference would mean the next two terms are ...

11 +16.5 = 27.5

27.5 + 16.5 = 44

These descriptions match those offered by the students, so both could be correct.

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A machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%). Prior to shipm

AURORKA [14]

Answer:

(a) 0.0686

(b) 0.9984

Step-by-step explanation:

Given that a machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%).

Let A, B, and C be the events of defect-free, slightly defective, and the defective parts produced by the machine.

So, from the given data:

P(A)=0.90, P(B)=0.03, and P(C)=0.07.

Let E be the event that the part is disregarded by the inspection machine.

As a part is incorrectly identified as defective and discarded 2% of the time that a defect free part is input.

So, $P\left(\frac{E}{A}\right)=0.02$

Now, from the conditional probability,

$P\left(\frac{E}{A}\right)=\frac{P(E\cap A)}{P(A)}$

$\Rightarrow P(E\cap A)=P\left(\frac{E}{A}\right)\times P(A)$

$\Rightarrow P(E\cap A)=0.02\times 0.90=0.018\cdots(i)$

This is the probability of disregarding the defect-free parts by inspection machine.

Similarly,

$P\left(\frac{E}{A}\right)=0.40$

and $\Rightarrow P(E\cap B)=0.40\times 0.03=0.012\cdots(ii)$

This is the probability of disregarding the partially defective parts by inspection machine.

$P\left(\frac{E}{A}\right)=0.98$

and $\Rightarrow P(E\cap C)=0.98\times 0.07=0.0686\cdots(iii)$

This is the probability of disregarding the defective parts by inspection machine.

(a) The total probability that a part is marked as defective and discarded by the automatic inspection machine

$=P(E\cap C)$

$= 0.0686$ [from equation (iii)]

(b) The total probability that the parts produced get disregarded by the inspection machine,

$P(E)=P(E\cap A)+P(E\cap B)+P(E\cap C)$

$\Rightarrow P(E)=0.018+0.012+0.0686$

$\Rightarrow P(E)=0.0986$

So, the total probability that the part produced get shipped

$=1-P(E)=1-0.0986=0.9014$

The probability that the part is good (either defect free or slightly defective)

$=\left(P(A)-P(E\cap A)\right)+\left(P(B)-P(E\cap B)\right)$

$=(0.9-0.018)+(0.03-0.012)$

$=0.9$

So, the probability that a part is 'good' (either defect free or slightly defective) given that it makes it through the inspection machine and gets shipped

$=\frac{\text{Probabilily that shipped part is 'good'}}{\text{Probability of total shipped parts}}$

$=\frac{0.9}{0.9014}$

$=0.9984$

(c) The probability that the 'bad' (defective} parts get shipped

=1- the probability that the 'good' parts get shipped

=1-0.9984

=0.0016

5 0

2 years ago

Justin is exchanging dollars for rolls of quarters and rolls of dimes at a bank. Each roll of quarters has a value of $10 and ea

Vitek1552 [10]

Well, it really depends but it could be 9 rolls of quarters, 5 rolls of quarters and 8 rolls of dimes, 4 rolls of quarters and 10 rolls of dimes, 3 rolls of quarters and 12 rolls of dimes, etc.

6 0

2 years ago

Read 2 more answers

Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when

bija089 [108]

Answer:

$f(x) = k(x - \frac{3}{2})$

Step-by-step explanation:

Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when x = $\frac{3}{2}$ and y = 0.

Now, as x = $\frac{3}{2}$ is a solution of the equation, y = f(x) = 0, so, $(x - \frac{3}{2})$ will be a factor of the linear function y = f(x).

Therefore, we can write the possible equation for the line q will be

$f(x) = k(x - \frac{3}{2})$ . (Where k is any constant} (Answer)

8 0

2 years ago

A baseball glove is on sale for $34.00, which is 15% off of its original price. What was the original price of the baseball glov

Y_Kistochka [10]

Answer: $40.00

Step-by-step explanation:

To find the original price, you would need to utilize the equation Original Price = Sales Price ÷ (1 - Discount). In this equation, Discount refers to the percentage of discount.

Original Price = $34.00 ÷ (1 - 0.15)

Original Price = $34.00 ÷ (0.85)

Original Price = $40.00

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2 years ago

There are 5 cards with a picture of a rose and 1 card with a picture of a daisy. Olga keeps all the cards face down on the table

HACTEHA [7]

The correct answer is 4 over 5

4 0

2 years ago