Okay, so Sang is standing 20 yards away from one corner, and Jazmin is standing 99 yards away from the same corner. If this is a rectangle (I like visuals, so I'll use them to explain), then:
99ft
A ------------------------- B
| |
20 ft | |
| |
C -------------------------- D
The question is asking you to solve for the diagonal line between points C and B. If you imagine a line there, you actually have the rectangle split into two triangles. So if you have triangle ABC, side CB would be the longest line, or the hypotenuse. That means you can use the Pythagorean Theorem to solve the problem.
A^2 + B^2 = C^2
99^2 + 20^2 = C^2
9,801 + 400 = C^2
10,201 = C^2
Now you solve for the square root of 10,201 to get C.
sqr (10,201) = C
C = 101 yards
Answer:
The correct option is option B.
Step-by-step explanation:
The given function is
We can rearrange the function as
⇒ 3(x - 4)² - 2 = 18y - 36
⇒ 3(x - 4)² = 18y - 34
⇒ 
⇒ 
⇒ 
Therefore, the inverse function will be, 
Therefore, the correct option is option B. (Answer)
Answer:
a) 1 tsp.
b) 1.5 tsp.
c) 2 tsp.
Step-by-step explanation:
Complete Correct Question
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog
- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
Solution
a) 18 kg adult dog
The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
9 kg dog weight = (1/2) tsp
18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.
b) 6 kg cat
The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
1 kg cat = (1/4) tsp
6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.
c) 18 kg pregnant dog
The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
4.5 kg dog weight = (1/2) tsp
18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.
Hope this Helps!!!
Since <span>x</span> contains the variable to solve for, move it to the left side of the equation by subtracting <span>x</span> from both sides.<span><span><span><span><span>2m</span><span><span>−n</span>x</span></span><span>−x</span></span>=4
</span></span>Since 2m does not contain the variable to solve for, move it to the right side of the equation by subtracting 2m from both sides.<span><span><span><span><span>n</span>x</span><span>-x</span></span>=<span><span><span>-2</span>m</span>+4</span></span></span>Factor <span>x</span> out of <span><span><span><span>−n</span>x</span><span>−x</span></span></span><span><span><span>x<span>(<span><span>−n</span><span>−1</span></span>)</span></span>=<span><span><span>−2</span>m</span>+4</span></span></span>Divide each term by <span><span><span>−n</span><span>−1</span></span><span><span>-n</span><span>-1</span></span></span> and simplify.<span>x=<span><span><span>2<span>(<span>m<span>−2</span></span>)/</span></span><span>n+1</span></span></span></span>
