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algol13
2 years ago
15

713.49 written in a standard form

Mathematics
1 answer:
Vikki [24]2 years ago
7 0

Answer: one hundred  seven thirteen and forty-nine hundreds

Step-by-step explanation: Standard form is a way of writing down very large or very small numbers easily. 103 = 1000, so 4 × 103 = 4000 . So 4000 can be written as 4 × 10³ . This idea can be used to write even larger numbers down easily in standard form.

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Which of the following shows the division problem below in synthetic division form?
MissTica

Answer:

Choice D

Step-by-step explanation:

Given division problem is \frac{5x^2+9x-6}{x+2}

Now we need to find about which of the given choices shows the division problem below in synthetic division form.

To convert into synthetic division form, we set denominator =0 so we get

x+2=0 or x=-2

Hence we divide by -2

Now collect coefficients of numerator for the dividend part

Coefficients of  5x^2+9x-6 are 5 9 -6

Hence correct choice is D

8 0
2 years ago
Read 2 more answers
Please answer! I’m desperate.
lara31 [8.8K]

Answer:

Hi! This is the answer for part C, or finding the factors.

Step-by-step explanation:

Checked by my teacher. hope this part helps. Will post the rest soon.

8 0
1 year ago
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Se the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x2
pishuonlain [190]
\mathbf f(x,y,z)=x^2\sin y\,\mathbf i+x\cos y\,\mathbf j-xz \sin y\,\mathbf k
\implies\nabla\cdot\mathbf f(x,y,z)=2x\sin y-x\sin y-x\sin y=0

which means

\displaystyle\iint_S\mathbf f(x,y,z)\,\mathrm dS=\iiint_R\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=0
8 0
2 years ago
Two sides of a triangle have lengths 12 m and 14 m. The angle between them is increasing at a rate of 2°/min. How fast is the le
Dvinal [7]

Answer:

1.692 m/min

Step-by-step explanation:

Let \theta be the angle between the two sides and x be the length of the third side. By cosine rule,

x^2 = 12^2+14^2-2\times12\times14\cos\theta = 340 - 336\cos\theta

x= \sqrt{340 - 336\cos\theta}

We differentiate x with respect to \theta by applying chain rule.

\dfrac{dx}{d\theta} = \dfrac{336\sin\theta}{2\sqrt{340 - 336\cos\theta}} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}}

Rate of change of \theta is 2

\dfrac{\theta}{dt} = 2

Rate of change of x is

\dfrac{dx}{dt} = \dfrac{dx}{d\theta}\times\dfrac{d\theta}{dt}

\dfrac{dx}{dt} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}} \times2=\dfrac{336\sin\theta}{\sqrt{340 - 336\cos\theta}}

At 60°,

\dfrac{dx}{dt} = \dfrac{336\sin60}{\sqrt{340 - 336\cos60}} = 1.692 \text{ m/min}

4 0
2 years ago
Geometry: Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
Kazeer [188]

It is given in the question that,

Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.

And

m \angle PQS = 2x+1
\\
m \angle RQS = 4x-15

Since QS bisects angle PQR, therefore

m \angle PQS = m \angle RQS

Substituting the values, we will get

2x+1=4x-15
\\
1+15 = 4x-2x
\\
2x = 16
\\
x = 8

6 0
1 year ago
Read 2 more answers
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